Ta có \(\frac{3}{2}-\frac{5}{2}.\left(1,2x-3\right)^2=-0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{3}{2}+0,9\)

\(\Rightarrow\frac{5}{2}.\left(1,2x-3\right)^2=\frac{21}{2}\)

\(\Rightarrow\left(1,2x-3\right)^2=\frac{21}{5}\)

đề sai hay mình sai ????

\(\left(\frac{-3}{2x}+\frac{1}{4}\right):\frac{1}{6}=\frac{-3}{2}\)

\(\Rightarrow\frac{-3}{2x}+\frac{1}{4}=\frac{-3}{2}.\frac{1}{6}=-\frac{1}{4}\)

\(\Rightarrow\frac{-3}{2x}=-\frac{1}{4}-\frac{1}{4}=-\frac{1}{2}\)

\(\Rightarrow\frac{-3}{2x}=\frac{-3}{6}\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

(-3/2x + 0,25) : 1/6 = -3/2

=> -3/2x + 0,25 = -3/2 . 1/6

=> -3/2x + 0,25 = -1/4

=> -3/2x = -1/4 - 0,25

=> -3,2x = -1/2

=> x = -1/2 : (-3/2)

=> x = 1/3

( 5/4x - 2/3 )^4 = 57/16 + 3/2

=> ( 5/4x - 2/3 )^4 = 81/16

=> ( 5/4x - 2/3 )^4 = 3^4/2^4

=> 5/4x - 2/3 = 3/2

=> 5/3x = 13/6

=> x = 13/10

      Vậy x = 13/10

\(\left(\frac{5}{4}x-\frac{2}{3}\right)^4-\frac{3}{2}=\frac{57}{16}\)

\(\left(\frac{5}{4}x-\frac{2}{3}\right)^4-\frac{3}{2}=\frac{57}{16}+\frac{3}{2}\)

\(\left(\frac{5}{4}x-\frac{2}{3}\right)=\frac{81}{16}\)

Ta xét 2th:

Th1: \(\frac{5}{4}x-\frac{2}{3}=\left(\frac{81}{16}\right)^{\frac{1}{4}}\)

\(\Rightarrow x=\frac{26}{15}\)

Th2: \(\frac{5}{4}x-\frac{2}{3}=-\left(\frac{81}{16}\right)^{\frac{1}{4}}\)

\(\Rightarrow x=-\frac{2}{3}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{26}{15}\\x=-\frac{2}{3}\end{cases}}\)

em ko giai duoc ,em lop 2

-3/2 - | 3x + 4 |.2/5= 2

<=> | 3x + 4 | = (2+3/2)/(2/5)

<=>  | 3x + 4 | = 35/4

<=>3x + 4 =35/4

Hoặc 3x + 4 = - 35/4

Tự giải nốt nha

Vì (x+1).(x-2)=-2

=> (x+1);(x-2) thuộc Ư(-2)={-2;-1;1;2}

Ta có bảng sau:

Vì x giống nhau nên ta chỉ chọn cặp x giống nhau

=> x=0 và x=1

Mik mới học lớp 6 nên chưa chắc nếu sai thì thông cảm nhé

(x+1) . (x-2) = -2

<=>x²-x-2=-2

<=>x²-x=0

<=>x(x-1)=0

<=>x=0 hoặc x-1=0

<=>x=0 hoặc 1

\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\left(\frac{-4}{5}\right)^3\)

\(\frac{3}{5}-\frac{2}{3}x=\frac{-4}{5}\)

\(\frac{2}{3}x=\frac{7}{5}\)

\(x=\frac{21}{10}\)

\(\left(\frac{3}{5}-\frac{2}{3}.x\right)^3=\frac{-64}{125}\)

\(\Leftrightarrow\left(\frac{3}{5}-\frac{2}{3}.x\right)^3=\left(-\frac{4}{5}\right)^3\)

\(\Rightarrow\frac{3}{5}-\frac{2}{3}.x=-\frac{4}{5}\)

\(\Leftrightarrow\frac{2}{3}.x=\frac{3}{5}-\left(-\frac{4}{5}\right)\)

\(\Leftrightarrow\frac{2}{3}.x=\frac{3}{5}+\frac{4}{5}\)

\(\Leftrightarrow\frac{2}{3}.x=\frac{7}{5}\)

\(\Leftrightarrow x=\frac{7}{5}:\frac{2}{3}\)

\(\Leftrightarrow x=\frac{21}{10}\)

Vậy \(x=\frac{21}{10}\)

\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\frac{-64}{125}\)

\(\left(\frac{3}{5}-\frac{2}{3}x\right)^3=\left(\frac{-4}{5}\right)^3\)

\(\frac{3}{5}-\frac{2}{3}x=\frac{-4}{5}\)

\(\frac{9}{15}-\frac{10x}{15}=\frac{-12}{15}\)

\(-\frac{10x}{15}=\frac{9}{15}-\frac{-12}{15}\)
\(\text{ }-10x=9+12\)

\(-10x=21\)

\(x=\frac{-21}{10}\)

k nha