a)   \(-x+821+534=499+\left(x-84\right)\)

\(-x-x=499-84-821-534\)

\(-2x=-940\)

\(x=470\)

b)  \(x-96=\left(448-x\right)-150\)

\(x+x=448-150+96\)

\(2x=394\)

\(x=197\)

c)  \(-\left(754+x\right)=\left(x-12-741\right)-23\)

\(-754-x=x-12-741-23\)

\(-x+x=-12-741-23+754\)

\(0x=2\)

\(x\)ko tồn tại

d) \(\left(6+x\right)-\left(17-21\right)=-25\)

\(6+x-17+21=-25\)

\(x=-25-6+17-21\)

\(x=-35\)

e)  \(17-\left(x+2\right)=3\)

\(17-x-2=3\)

\(-x=3-17+2\)

\(-x=-12\)

\(x=12\)

h)  \(-10-\left(31-x\right)=40\)

\(-10-31+x=40\)

\(x=40+10+31\)

\(x=81\)

k mk nha bạn    

a) - x + 821 + 534 = 499 + ( x - 84 )

<=> -x + 821 + 534 = 499 + x - 84

<=> 2x = 940

<=> x = 470

b, x - 96 = ( 448 - x ) - 150

<=> x - 96 = 448 - x - 150

<=> 2x = 394

<=> x = 157

Cac phan con lai tuong tu

Bài 1:

a. Ta có: $1953=3^2.7.31$

$777=3.7.37$

$\Rightarrow UCLN(1953, 777) = 3.7=21$

b. Đề khó hiểu quá. Bạn xem lại/

Bài 2: Thiếu dấu giữa các số. Bạn xem lại.

nhanh đi mình cần gấp 

giúp mình với

kho qua khong giai duoc 

2: x=3

3: x=18

1) \(x=51\)

2) \(x=3\)

3) \(x=18\)

4) \(x=2\)

5) \(x=7\)

Bài 4:

a: xy=-2

=>\(x\cdot y=1\cdot\left(-2\right)=\left(-2\right)\cdot1=\left(-1\right)\cdot2=2\cdot\left(-1\right)\)

=>\(\left(x,y\right)\in\left\{\left(1;-2\right);\left(-2;1\right);\left(-1;2\right);\left(2;-1\right)\right\}\)

b: \(\left(x-1\right)\left(y+2\right)=-3\)

=>\(\left(x-1\right)\cdot\left(y+2\right)=1\cdot\left(-3\right)=\left(-3\right)\cdot1=-1\cdot3=3\cdot\left(-1\right)\)

=>\(\left(x-1;y+2\right)\in\left\{\left(1;-3\right);\left(-3;1\right);\left(-1;3\right);\left(3;-1\right)\right\}\)

=>\(\left(x,y\right)\in\left\{\left(2;-5\right);\left(-2;-1\right);\left(0;1\right);\left(4;-3\right)\right\}\)

Bài 3:

a: \(x\left(x+9\right)=0\)

=>\(\left[{}\begin{matrix}x=0\\x+9=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=0\\x=-9\end{matrix}\right.\)

b: \(\left(x-5\right)^2=9\)

=>\(\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=3+5=8\\x=-3+5=2\end{matrix}\right.\)

c: \(\left(7-x\right)^2=-64\)

mà \(\left(7-x\right)^2>=0\forall x\)

nên \(x\in\varnothing\)

Bài 2:

a: \(\left(-31\right)\cdot x=-93\)

=>\(31\cdot x=93\)

=>\(x=\dfrac{93}{31}=3\)

b: \(\left(-4\right)\cdot x=-20\)

=>\(4\cdot x=20\)

=>\(x=\dfrac{20}{4}=5\)

c: \(5x+1=-4\)

=>\(5x=-4-1=-5\)

=>\(x=-\dfrac{5}{5}=-1\)

d: \(-12x+1=-4\)

=>\(-12x=-4-1=-5\)

=>\(12x=5\)

=>\(x=\dfrac{5}{12}\)

17x + 3. ( -16x – 37) = 2x + 43 - 4x

<=>17x-48x-111=-2x+43

<=>-29x=154

<=> \(x=-\frac{154}{29}\)

-3. (2x + 5) -16 < -4. (3 – 2x)

\(\Leftrightarrow-6x-31< -12+8x.\)

\(\Leftrightarrow-14x< 19\Rightarrow x< -\frac{19}{14}\)

a) ( x + 216 ) : 61 + 1 = 202

( x + 216 ) : 61 = 201

( x + 216 ) = 12261

x = 12045

b) 1818 : ( 6x - 37 ) + 1 = 19

1818 : ( 6x - 37 ) = 18

( 6x - 37 ) = 101

6x = 138

x = 23

c) ( x : 23 + 45 ) x 67 + 3 = 8914

( x : 23 + 45 ) x 67 = 8911

x : 23 + 45 = 133

x : 23 = 88

x = 2024

(x + 216) : 61 + 1 = 202

=> (x + 216) : 61 = 201

=> x + 216 = 12261

=> x = 12045

vậy_

1818 : (6x - 37) + 1 = 19

=> 1818 : (6x - 37) = 18

=> 6x - 37 = 101

=> 6x = 138

=> x = 23

vậy_

(x : 23 + 45) x 67 + 3 = 8914

=> (x : 23 + 45) x 67 = 8911

=> x : 23 + 45 = 133

=>x : 23 = 88

=> x = 2024

vậy_

1

a, -114

b, -1000

c, 87

d, 164

e, 981

2

a, x=14

b, x E {-32,2}

c, đề sai

d, 262

e, -3

g, đề sai

h, -3