b) x^10=1x

=> x=0 ; 1

c)(2x-15)^5=(2x-15)^3

=> (2x-15)^4 = (2x-15)^2

=> (2x-15)^2 =1

=> 2x-15=1

=> x=8 

2\(^x\)- 15 = 17

\(\Rightarrow\)2\(^x\) =  32

\(\Rightarrow\)x  = 5

2^x-15=17

=>2^x=17+15

=2^x=32

=>2^x=2^5

=>x=5

e) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\cdot\left(2x-15\right)^2-\left(2x-15\right)^3=0\)

\(\Rightarrow\left(2x-15\right)^3\cdot\left[\left(2x-15\right)^2-1\right]=0\)

\(\Rightarrow\left(2x-15\right)^3=0\) hoặc \(\left(2x-15\right)^2-1=0\)

+)TH1: \(\left(2x-15\right)^3=0\)

\(\Rightarrow2x-15=0\)

\(\Rightarrow2x=15\)

\(\Rightarrow x=\frac{15}{2}\)

+)TH2: \(\left(2x-15\right)^2-1=0\)

\(\Rightarrow\left(2x-15\right)^2=1\)

\(\Rightarrow\left[{}\begin{matrix}2x-15=1\\2x-15=-1\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}2x=16\\2x=14\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)

Vậy \(x=\frac{15}{2}\) hoặc \(x=8\) hoặc \(x=7\)

a) \(2^x-17=15\Rightarrow2^x=32\)

Mà \(2^5=32\Rightarrow x=5\)

Vậy x = 5

b)\(\left(7x-11\right)^3=2^5\cdot5^2+200\)

\(\Rightarrow\left(7x-11\right)^3=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Vậy x = 3

c)\(x^{10}=1^x\Rightarrow x^{10}=1\)(số 1 có luỹ thừa là bao nhiêu thì vẫn là 1 thui)\(\Rightarrow x=1\)

Vậy x = 1

d) \(x^{10}=x\Rightarrow x^{10}-x=0\)

\(\Rightarrow x\left(x^9-1\right)=0\)

\(\Rightarrow x=0\) hoặc \(x^9-1=0\)

+)TH1: \(x=0\)

+)TH2: \(x^9-1=0\Rightarrow x^9=1\Rightarrow x=1\)

Vậy x = 0 hoặc x = 1

tìm số tự nhiên x biết

a, 2^x - 15 =17

=> 2^x = 17 + 15 = 32

=> 2^x = 2⁵

=> x = 5

b, ( 7x - 11)³ = 2⁵ x 5²+200

=> ( 7x - 11 )³ = 32 . 25 + 200

=> ( 7x - 11 )³ = 1000

=> ( 7x - 11 )³ = 10³

=> 7x - 11 = 10

=> 7x = 10 + 11 = 21

=> x = 21 : 7 = 3

a) 2^x-15= 17

    2^x      = 17-15

   2^x        =  2

   2^x         =  2¹

  x             =   1                      

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=3\)

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Rightarrow\left(7x-11\right)^3=32.25+200\)

\(\Rightarrow\left(7x-11\right)^3=800+200\)

\(\Rightarrow\left(7x-11\right)^3=1000=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Ta có: \(\left(7x-11\right)^3=2^5+5^2+200=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Trả lời:

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=32.25+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=3\)

Vậy\(x=3\)

Hok tốt!

Good girl

a) 2^x - 15 = 17

2^x = 2⁵

b) ( 7x - 11 )³ = 2⁵. 5² + 200

(7x - 11)³ = 32 . 25 + 200

(7x -11)³ = 1000

(7x-11)³ = 10³

7x - 11 = 10

7x = 10+11

7x = 21

x = 21 : 7

x = 3

like nha

a) \(2^x=16\)

\(2^x=2^4\)

\(\Rightarrow x=4\)

vay \(x=4\)

b) \(4^x=64\)

\(4^x=4^3\)

\(\Rightarrow x=3\)

vay \(x=3\)

c) \(15^x=225\)

\(15^x=15^2\)

\(\Rightarrow x=2\)

vay \(x=2\)

d) \(2^x-15=17\)

\(2^x=32\)

\(2^x=2^5\)

\(\Rightarrow x=5\)

vay \(x=5\)

e) \(2^x-64=2^6\)

\(2^x=2^6+64\)

\(2^x=128\)

\(2^x=2^7\)

\(\Rightarrow x=7\)

vay \(x=7\)

f) \(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

vay \(x=3\)

a, x=4

b, x=3

c, x=2

d, =2