1a) 25 .8 - 12.5 + 272 :17 - 8

= 200 -  60 + 16 - 8

= 140+16-8

= 156 - 8

= 148

b) 125: 25 +14 - 142 : 71

= 5 + 14 - 2 

= 19 - 2 = 17

c) 13. 17 - 256: 16 + 14 : 7 - 1

= 221 - 16 + 2 - 1 

= 205 + 2 - 1 

= 207 - 1 = 206

d) 15 . 24 - 14 . 5 (145 : 5 - 27)

= 360 - 70 (29- 27)

= 360 - 70 . 2

= 360 - 140

= 220

2a) 37 + x = 55

               x= 55 - 37

               x = 18

b) x- 31 = 24

     x       = 24 + 31

     x        = 55

c) 21 (x-11) = 21

        x - 11   = 21 : 21

          x        = 1 +11

           x       = 12

d ) 9. (x - 29)= 0

           x - 29 = 0 :9

             x       = 29

e) (x - 1954) . 5 = 50

         x - 1954   = 50 : 5

          x             = 1964

f ) 30 . 60 - x = 30

        1800 - x   = 30

             x        = 1800 - 30

             x        = 1770

Viết mỏi tay quá huhuh

Cảm ơn nghen

a)  (-37 - 17) . (-9) + 35 . (-9 - 11)

=-54*(-9)+35*(-20)

=486+(-700)

=-214

b) (-25) . (75 - 45) - 75 . ( 45 - 25)

=(-25)*30-75*20

=-750-1500

=-2250

bài 2 phần a sai đề r` tui lm phần b thôi

\(x-17=\left(-8\right)-17\)

\(\Rightarrow x=-8-17+17\)

\(\Rightarrow x=-8\)

\(25-\left(11+x\right)=x-\left(34-18\right)\)

\(\Rightarrow25-11-x=x-34+18\)

\(\Rightarrow-x-x=-34+18+11-25\)

\(\Rightarrow-2x=-30\)

\(\Rightarrow x=15\)

\(6-\left(17-x\right)=3x-7\)

\(\Rightarrow6-17+x=3x-7\)

\(\Rightarrow x-3x=-7+17-6\)

\(\Rightarrow-2x=4\)

\(\Rightarrow x=-2\)

a) \(x\left(x-6\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)

b) \(\left(-7-x\right)\left(-x+5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}-7-x=0\\-x+5=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-7\\x=-5\end{matrix}\right.\)

c) \(\left(x+3\right)\left(x-7\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x+3=0\\x-7=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-3\\x=7\end{matrix}\right.\)

d) \(\left(x-3\right)\left(x^2+12\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-3=0\\x^2+12=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x^2=-12\text{(vô lý)}\end{matrix}\right.\)

\(\Rightarrow x=3\)

e) \(\left(x+1\right)\left(2-x\right)\ge0\)

\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x+1\ge0\\2-x\ge0\end{matrix}\right.\\\left[{}\begin{matrix}x+1\le0\\2-x\le0\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x\ge-1\\x\le2\end{matrix}\right.\\\left[{}\begin{matrix}x\le-1\\x\ge2\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}-1\le x\le2\\x\in\varnothing\end{matrix}\right.\)

\(\Rightarrow-1\le x\le2\)

f) \(\left(x-3\right)\left(x-5\right)\le0\)

\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x-3\le0\\x-5\ge0\end{matrix}\right.\\\left[{}\begin{matrix}x-3\ge0\\x-5\le0\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x\le3\\x\ge5\end{matrix}\right.\\\left[{}\begin{matrix}x\ge3\\x\le5\end{matrix}\right.\end{matrix}\right.\)

\(\Rightarrow3\le x\le5\)

a) =>\(\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)

b => \(\left[{}\begin{matrix}-7-x=0\\-x+5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-7\\x=5\end{matrix}\right.\)

d) => \(\left[{}\begin{matrix}x-3=0\\x^2+12=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x^2=-12\end{matrix}\right.\)(vô lí) => x=3

\(a,2-x=17-\left(-5\right)\)

\(\Rightarrow2-x=17+5\)

\(\Rightarrow2-x=22\)

\(\Rightarrow x=2-22\)

\(\Rightarrow x=-20\)

Vay...

\(b,11-\left(15+11\right)=x-\left(25-9\right)\)

\(\Rightarrow11-26=x-16\)

\(\Rightarrow-15=x-16\)

\(\Rightarrow-15+16=x\)

\(\Rightarrow x=1\)

a) \(x+5=20-\left(12-7\right)\)

\(\Rightarrow x+5=20-5\)

\(\Rightarrow x+5=15\)

\(\Rightarrow x=15-5\)

\(\Rightarrow x=10\)

b) \(15-\left(3+2x\right)=2^2\)

\(\Rightarrow3+2x=15-4\)

\(\Rightarrow3+2x=11\)

\(\Rightarrow2x=11-3\)

\(\Rightarrow2x=8\)

\(\Rightarrow x=\dfrac{8}{2}\)

\(\Rightarrow x=4\)

c) \(-11-\left(19-x\right)=50\)

\(\Rightarrow19-x=-11-50\)

\(\Rightarrow19-x=-61\)

\(\Rightarrow x=61+19\)

\(\Rightarrow x=80\)

d) \(159-\left(25-x\right)=43\)

\(\Rightarrow25-x=159-43\)

\(\Rightarrow25-x=116\)

\(\Rightarrow x=25-116\)

\(\Rightarrow x=-91\)

e) \(\left(79-x\right)-43=-\left(17-52\right)\)

\(\Rightarrow\left(79-x\right)-43=52-17\)

\(\Rightarrow79-x-43=35\)

\(\Rightarrow36-x=35\)

\(\Rightarrow x=1\)

f) \(\left(7+x\right)-\left(21-13\right)=32\)

\(\Rightarrow7+x-8=32\)

\(\Rightarrow x-1=32\)

\(\Rightarrow x=32+1\)

\(\Rightarrow x=33\)

g) \(-x+20=-15+8+13\)

\(\Rightarrow-x+20=6\)

\(\Rightarrow x=20-6\)

\(\Rightarrow x=14\)

h) \(-\left(-x+13-142\right)+18=55\)

\(\Rightarrow x-13+142+18=55\)

\(\Rightarrow x+147=55\)

\(\Rightarrow x=55-147\)

\(\Rightarrow x=-92\)

a)

Ư(28)\(=\left\{1,2,4,7,14,28\right\}\)

1. THực hiện phép tính :

a) 17 - 25 + 55 - 17

= ( 17 - 17 ) + ( -25 + 55 )

= 0 + 30 = 30

b) 25 - (-75) + 32 - (32 + 75)

= 25 + 75 + 32 - 32 - 75

= 25 + ( 75 - 75 ) + ( 32 - 32 )

= 25 + 0  +  0 = 25

c) (-5).8.(-2).3

= [(-5).(-2)].(8.3)

= 10 . 24 = 240

d) (-15) + (- 122) = - ( 15 + 122 ) = -137

e) /-127/ - 18.(5-6) 

= 127 - 18.(-1)

= 127 - ( -18 ) = 127 + 18 = 145

Trả lời

1.Thực hiện phép tính :

a)17-25+55-17

=(17-17)-25+55

=0-25+55

=30

b)25-(-75)+32-(32+75)

=25+75+32-32-75

=25+(75-75)+(32-32)

=25+0+0

=25

c)(-5).8.(-2).3

=[(-5).(-2)].3.8

=10.24

=240

d)(-15)+(-122)

=(-137)

e)|-127|-18.(5-6)

=127-18.(-1)

=127.(-18)

=(-2286)

Bài 2:

a)Ư (-8)={-1;-2;-4;-8}

b)B (-11)={-11;-22;-33;-44;-55}

Bài 3:

a)-13+x=39

      =>x=39+13

      =>x=52

b)3x-(-17)=14

   3x+17   =14

   3x          =14-17

   3x          =(-3)

    x           =(-3):3

   x            =(-1)

c)|x+9|.2=10

   |x+9|    =10:2

   |x+9|    =5

   |x|        =5-9

   |x|        =-4

Vậy: x=4 hoặc -4

d)

12=2².3

10=2.5

BCNN (12;10)=2².3.5=60

BC (12;10) = {60;120;180}

Vậy x có thể là 1 trong 3 số trên: 60;120;180.