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6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001
Câu 1:
a. $3\frac{2}{3}+2\frac{1}{2}=(3+2)+(\frac{2}{3}+\frac{1}{2})=5+\frac{7}{6}=6+\frac{1}{6}=6\frac{1}{6}$
b. \(2\frac{1}{2}\times 3\frac{2}{5}=\frac{5}{2}\times \frac{17}{5}=\frac{17}{2}\)
c.
\(3\frac{1}{3}: 4\frac{1}{4}=\frac{10}{3}: \frac{17}{4}=\frac{40}{51}\)
d.
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=(3+4-5)+(\frac{1}{2}+\frac{5}{7}-\frac{5}{14})=2+\frac{6}{7}=2\frac{6}{7}\)
Câu 2:
a. $x\times \frac{2}{7}=\frac{6}{11}$
$x=\frac{6}{11}: \frac{2}{7}=\frac{21}{11}$
b. $x: \frac{3}{2}=\frac{1}{4}$
$x=\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$
mk k chắc
x + x * 1/3 : 2/9 + x : 2/7 = 252
x + x * 3/2 + x * 2/7 = 252
x * ( 1 + 3/2 + 2/7 ) =252
x * 39/14 =252
x = 252 : 39/14
x = 3528/39
\(x\times\frac{1}{2}\)\(+x\times\frac{1}{4}\)\(+x\times\frac{1}{8}\)\(=\frac{21}{24}\)
\(x\times\frac{1}{2}\)\(+x\times\frac{1}{4}\)\(=\frac{21}{24}\)\(\div\frac{1}{8}\)
\(x\times\frac{1}{2}\)\(+x\times\frac{1}{4}\)\(=\frac{168}{24}\)
\(x\times\frac{1}{2}\)\(=\)\(\frac{168}{24}\div\frac{1}{4}\)
\(x\times\frac{1}{2}\)\(=\frac{1344}{24}\)
\(x=\frac{1344}{24}\div\frac{1}{2}\)
\(x=112\)
Nếu : 2 x X + 1 = 8
Thì : 4 x X + 1 = ?
Ta có:
2 x X + 1 = 8
2 x X = 8 - 1
2 x X = 7
X = 7 : 2
X = 3,5
Vậy X = 3,5 ...
Nên: 4 x 3,5 + 1
= 14 + 1
= 15
... Vậy: 4 x X + 1 = 15
~ Hok T ~