`a)-5/6-x=7/12+[-1]/3`

   `-5/6-x=1/4`

   `x=-5/6-1/4`

   `x=-13/12`

`b)(4,5-2x).(-1 4/7)=11/14`

   `(4,5-2x).(-11/7)=11/14`

    `4,5-2x=11/14:(-11/7)=-0,5`

    `2x=4,5-(-0,5)=5`

    `x=5:2=2,5`

`c)(2/11+1/3)x=(1/7-1/8).56`

   `17/33 x=1/56 .56=1`

      `x=33/17`

tìm x biết:

(3x-1) [- 1/2x+5]=0

1/4+1/3:(2x-1)=-5

[2x+3/5]² - 9/25=0

-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6

[x+1/2]x [2/3-2x]=0

17/2-|2x-3/4|=-7/4

2/3x-1/2x =5/12

(x+1/5)²+17/25=26/25

[x.44/7+3/7].11/5-3/7=-2

3[3x-1/2]+1/9=0

Toán lớp 6Tìm x

 Trả lời  Câu hỏi tương tự

Chưa có ai trả lời câu hỏi này,bạn hãy là người đâu tiên giúp nguyenvanhoang giải bài toán này !

3(3x-1/2)^3+1/9=0

2:

a: x=2,4-0,4=2

b: =>2x=-1,5+0,8=-0,7

=>x=-0,35

c: =>x-16=-15

=>x=1

a: =>2x-x=-5/2-1/3

=>x=-17/6

b: =>4(x-2)²=36

=>(x-2)²=9

=>x-2=3 hoặc x-2=-3

hay x=5 hoặc x=-1

c: =>2x+1/2=5/6

=>2x=1/3

hay x=1/6

a: =>2x-x=-5/2-1/3

=>x=-17/6

b: =>4(x-2)²=36

=>(x-2)²=9

=>x-2=3 hoặc x-2=-3

hay x=5 hoặc x=-1

c: =>2x+1/2=5/6

=>2x=1/3

hay x=1/6

[x+1]:25=3

x+1=25*3

x+1=75

x=75-1=74

12:[x-3]=6x-3=12:6

x-3=2

x=3+2

x=5

4[x-1]:5=8

4[x-1]=5.8

4[x-1]=40

x-1=40:4

x-1=10

x=10+1=11

9[x+3]-25=11

9[x+3]=25+11=36

x+3=36:9=4

x=4-3=1

75:[x-2]=1

x-2=75:1=75

x=75+2=77

[2x-5]-7=6

2x-5=7+6=13

2x=13+5=18

x=18:2=9

k mk nha mk cầu xin bn đó công mk làm mà

tự mà làm 

dễ như thế còn hỏi

a) Ta có: \(3\left(x+5\right)-3=2\left(x+1\right)+7\)

\(\Leftrightarrow3x+15-3=2x+2+7\)

\(\Leftrightarrow3x+12=2x+9\)

hay x=-3

b) Ta có: \(15-\left(x+2\right)^2=-1\)

\(\Leftrightarrow\left(x+2\right)^2=16\)

\(\Leftrightarrow\left[{}\begin{matrix}x+2=4\\x+2=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-6\end{matrix}\right.\)

c) Ta có: \(75-\left(2x+1\right)^3=11\)

\(\Leftrightarrow\left(2x+1\right)^3=64\)

\(\Leftrightarrow2x+1=4\)

hay \(x=\dfrac{3}{2}\)

a) Ta có: $3\left(x+5\right)-3=2\left(x+1\right)+7$

$\iff 3x+15-3=2x+2+7$

$\iff 3x+12=2x+9$

hay x=-3

b) Ta có: $15-{\left(x+2\right)}^2=-1$

$\iff {\left(x+2\right)}^2=16$

$\iff [\begin{array}{c}x+2=4\\ x+2=-4\end{array}\iff [\begin{array}{c}x=2\\ x=-6\end{array}$

c) Ta có: $75-{\left(2x+1\right)}^3$

`3(x+5)-3=2(x+1)+7`

`3x+15-3=2x+2+7`

`x=-3`

.

`15-(x+2)^2=-1`

`(x+2)^2=16`

`(x+2)^2=4^2=(-4)^2`

`[(x+2=4),(x+2=-4):}`

`[(x=2),(x=-6):}`

.

`75-(2x+1)^3=11`

`(2x+1)^3=64`

`(2x+1)^2=4^3`

`2x+1=4`

`x=3/2`

$3(x+5)-3=2(x+1)+7$

$3x+15-3=2x+2+7$

$x=-3$

.

$15-{(x+2)}^2=-1$

${(x+2)}^2=16$

${(x+2)}^2=4^2={(-4)}^2$

$[\begin{array}{c}x+2=4\\ x+2=-4\end{array}$

$[\begin{array}{c}x=2\\ x=-6\end{array}$