X- 9 = 21:5 

X- 9 = 4,2

x = 4,2 + 9

x = 13,2

X : 3 = 1,248 : 4

X : 3 = 0,312

x = 0,312 x 3

x = 0,936

x - 9 = 4,2

x = 4,2 + 9 =13,2

x : 3 = 0,312

x = 0,312 x 3 = 0,936

\(x+x\cdot3:\dfrac{2}{9}+x:\dfrac{2}{7}=252\)

\(\Leftrightarrow x+x\cdot3\cdot\dfrac{9}{2}+x\cdot\dfrac{7}{2}=252\)

\(\Leftrightarrow x\cdot18=252\)

hay x=14

a, 3/4 + 1/4.x=2

    1/4.x        = 2-3/4

     1/4.x      =5/4

     x           = 5/4:1/4

     x           = 5

b, x-2/3.9/4=2,5-1/2

    x-2/3.9/4=2

    x-2/3     =2:9/4

    x-2/3   =8/9

     x        = 8/9+2/3

     x         = 14/9

x*3,4=15,3

x = 15,3 : 3,4

x = 4,5

7,5:x=0,24

x = 7,5 : 0,24

x = 31,25

5/6:x=7/8

x = 5/6 : 7/8

x = 20/21

2/3*x=5/9

x = 5/9 : 2/3

x = 5/6

Xx3,4=15,3

X       = 15,3 : 3,4

X       =4.5

7,5:x=0,24

      x=7,5 : 0,24

      x= 31.25

5/6:x=7/8

      x=5/6 : 7/8

      x=  20/21

2/3xX=5/9

       X= 5/9 : 2/3

       X= 5/6

Giải:

\(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+...+\dfrac{1}{x.\left(x+2\right)}=\dfrac{16}{99}\) 

\(\dfrac{1}{2}.\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{x.\left(x+2\right)}\right)=\dfrac{16}{99}\) 

\(\dfrac{1}{2}.\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{16}{99}\) 

                           \(\dfrac{1}{2}.\left(\dfrac{1}{3}-\dfrac{1}{x+2}\right)=\dfrac{16}{99}\) 

                                     \(\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{16}{99}:\dfrac{1}{2}\) 

                                     \(\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{32}{99}\) 

                                             \(\dfrac{1}{x+2}=\dfrac{1}{3}-\dfrac{32}{99}\) 

                                             \(\dfrac{1}{x+2}=\dfrac{1}{99}\) 

\(\Rightarrow x+2=99\) 

           \(x=99-2\) 

           \(x=97\) 

Chúc em học tốt!

\(\dfrac{1}{3x5}+\dfrac{1}{5x7}+\dfrac{1}{7x9}+...+\dfrac{1}{x\left(x+2\right)}=\dfrac{16}{99}\)

\(=\dfrac{1}{2}\left(\dfrac{2}{3x5}+\dfrac{2}{5x7}+...+\dfrac{2}{x\left(x+2\right)}\right)=\dfrac{16}{99}\)

\(=\dfrac{2}{3x5}\)\(+\dfrac{2}{5x7}+...+\dfrac{2}{x\left(x+2\right)}=\dfrac{32}{99}\)

\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}+.....+\dfrac{1}{x}-\dfrac{1}{x+2}=\dfrac{32}{99}\)

\(=\dfrac{1}{3}-\dfrac{1}{x+2}=\dfrac{32}{99}=>x=97\)

Bài 1 :

(4/5 + 3/10 - 1/5) x 6 : 4/7

= 9/10 x 6 : 4/7

= 27/5 : 4/7

= 189/20

2007 x 76 - 75 x 2007 - 2007

= 2007 x (76 - 75 - 1)

= 2007 x 0

= 0

(47,5 + 8,6 x 4,5 - 105)

= 47,5 + 38,7 - 105

= 86,2 - 105

= -94/5

Bài 2 :

a) x : 2/3 = 10

           x = 10 x 2/3

           x = 20/3

theo cách đó tự làm

dễ **** mình giải cho