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x - 7 = 15 - (-21)
x - 7 = 36
x = 36 + 7
x = 43
b) 3x + 17 = 2
3x = 2 - 17
3x = -15
x = -5
c) ( x - 9) = 45 - ( -35)
x - 9 = 80
x = 80 + 9
x = 89
a/ \(15-\left(x-7\right)=-21\)
\(15-x+7=-21\)
\(x=15-\left[\left(-21\right)-7\right]=15-\left(-28\right)=43\)
b/\(3x+17=2\)
\(3x=2-17=-15\)
\(x=-\frac{15}{3}=-5\)
c/\(45-\left(x-9\right)=-35\)
\(45-x+9=-35\)
\(x=45-\left[\left(-35\right)-9\right]=89\)
d/\(\left(-5\right)+x=15\)
\(x=15-\left(-5\right)=20\)
e/\(2x-\left(-17\right)=15\)
\(2x=15-17=-2\)
\(x=-\frac{2}{2}=-1\)
g/ \(Ix-2I=3\)
TH1: \(x-2=3\)
\(x=3+2=5\)
TH2: \(x-2=-3\)
\(x=\left(-3\right)+2=-1\)
=> \(x\in\left\{-1;5\right\}\)
a)x-2=6-5x-16
6x= -8
x= -4/3
b)-5x-(-3)-x=13-x
-5x+3-x=13-x
-5x=10
x=-2
c)15-(x-7)=-21-x
15-x+7=-21-x
22=-21 ( vô lí)
x không có giá trị
D)3x+17=2+3x+15
17=17
x có vô số giá trị
e) x-45-(x-9)=-35-x
x-45-x+9=-35-x
-x=1
x=-1
f) -5+x=15-x-2x
4x=20
x=5
g) 2x-(-17) =15
2x+17=15
2x=-2
x=-1
1,15-(x-7)=-21
x-7=15-(-21)
x-7= 36
x =36+7
x = 43
2,3x+17=2
3x =2-17
3x = -15
x = -15:3
x = -5
3,45-(x-9)=-35
x-9=45-(-35)
x-9=80
x=80+9
x=89
4,(-5)+x=15
x=15-(-5)
x=20
5,2x-(-17)=15
2x+17=15
2x=15-17
2x=-2
x=-2:2
x=-1
3/-7=13
o l m . v n
Toán lớp 6
Lê Hà Vy 24 tháng 4 2016 lúc 18:05
Báo cáo sai phạm
1,15-(x-7)=-21
x-7=15-(-21)
x-7= 36
x =36+7
x = 43
2,3x+17=2
3x =2-17
3x = -15
x = -15:3
x = -5
3,45-(x-9)=-35
x-9=45-(-35)
x-9=80
x=80+9
x=89
4,(-5)+x=15
x=15-(-5)
x=20
5,2x-(-17)=15
2x+17=15
2x=15-17
2x=-2
x=-2:2
x=-1
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f) (x – 5)2 = 9
a) 3x – 15 = 25 – 5x
=> 3x + 5x = 25 + 15
=> 8x = 40
=> x = 5
b) 3x - 17 = 2x – 7
=> 3x - 2x = -7 + 17
=> x = 10
c) 2x – 17 = – (3x – 18)
=> 2x - 17 = -3x + 18
=> 2x + 3x = 18 + 17
=> 5x = 35
=> x = 7
d) 3x – 14 = 2(x – 9) + 1
=> 3x - 14 = 2x - 18 + 1
=> 3x - 2x = -18 + 1 + 14
=> x = -3
f) (x – 5)2 = 9
\(\Rightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
a) Ta có: \(3x-15=25-5x\)
\(\Leftrightarrow3x-15-25+5x=0\)
\(\Leftrightarrow8x-40=0\)
\(\Leftrightarrow8x=40\)
hay x=5
Vậy: x=5
b) Ta có: \(3x-17=2x-7\)
\(\Leftrightarrow3x-17-2x+7=0\)
\(\Leftrightarrow x-10=0\)
hay x=10
Vậy: x=10
c) Ta có: \(2x-17=-\left(3x-18\right)\)
\(\Leftrightarrow2x-17=-3x+18\)
\(\Leftrightarrow2x-17+3x-18=0\)
\(\Leftrightarrow5x-35=0\)
\(\Leftrightarrow5x=35\)
hay x=7
Vậy: x=7
d) Ta có: \(3x-14=2\left(x-9\right)+1\)
\(\Leftrightarrow3x-14=2x-18+1\)
\(\Leftrightarrow3x-14-2x+18-1=0\)
\(\Leftrightarrow x+3=0\)
\(\Leftrightarrow x=-3\)
Vậy: x=-3
f) Ta có: \(\left(x-5\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-5=3\\x-5=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{2;8\right\}\)
a) \(5x-65=5.3^2 \\ 5x-65=45\\5x=45+65\\5x=110\\x=22\)
b) \(200-(2x+6)=4^3\\2x+6=200-4^3\\2x+6=136\\2x=130\\x=65\)
c) \(2(x-51)=2.2^3+20\\2(x-51)=16+20\\2(x-51)=36\\x-51=18\\x=51+18=69\)
d) \(135-5(x+4)=35\\5(x+4)=135-45\\5(x-4)=90\\x-4=18\\x=18+4=22\)
e) \((2x-4)(15-3x)=0\\2(x-2).3(5-x)=0\\(x-2)(5-x)=0\\ \left[ \begin{array}{l}x-2=0\\5-x=0\end{array} \right. \\ \left[ \begin{array}{l}x=2\\x=5\end{array} \right.\)
f) \(2^{x+1} . 2^{2014}=2^{2016} \\ (2^{x+1} . 2^{2014}):2^{2014}=2^{2016} :2^{2014} \\ 2^{x=1}=2^{2016-2014} \\2^{x+1}=2^2\\x+1=2\\x=1\)
g) \(15+(x-1)^3=43\\(x-1)^3=15-42\\(x-1)^3=-27\\(x-1)^3=(-3)^3\\x-1=-3\\x=-2\)
h) \(15-x=17+(-9)\\15-x=17-9\\15-x=8\\x=15-8\\x=7\)
i) \(|x-5|=|-7|+|-4|\\|x-5|=7+4\\|x-5|=11\\ \left[ \begin{array}{l}x-5=11\\x-5=-11\end{array} \right. \\ \left[ \begin{array}{l}x=16\\x=-6\end{array} \right.\)
k) \(|x-3|-12=-9+|-7|\\|x-3|-12=-9+7\\|x-3|-12=-2\\|x-3|=10 \\ \left[ \begin{array}{l}x-3=10\\x-3=-10\end{array} \right. \\ \left[ \begin{array}{l}x=13\\x=-7\end{array} \right.\)
1) 3x = 45 + 15 = 60
x = 60 : 3 = 20
2) 5x = 50 - 35 = 15
x = 15 : 5 = 3
3) (2x - 5) + 17 = 6
2x - 5 = 6 - 17
2x - 5 = -11
2x = -11 + 5
2x = -6
x = -6 : 2 = -3
4) 10 - 2(4 -3x) = -4
2(4 - 3x) = -4 - 10 = -14
4 - 3x = -14 : 2 = -7
3x = -7 - 4 = -18
x = -18 : 3 = -6
\(\left\{{}\begin{matrix}\left\{{}\begin{matrix}3x-15=45\Leftrightarrow3x=60\Leftrightarrow x=20\\35-5x=50\Leftrightarrow5x=-15\Leftrightarrow x=-3\end{matrix}\right.\\\left\{{}\begin{matrix}\left(2x-5\right)+17=6\Leftrightarrow2x+5=-11\Leftrightarrow2x=-16\Leftrightarrow x=-8\\10-2\left(4-3x\right)=-4\Leftrightarrow8-6x=14\Leftrightarrow6x=-6\Leftrightarrow x=-1\end{matrix}\right.\\\left\{{}\begin{matrix}-12+3\left(-x+7\right)=-18\Leftrightarrow-3x+21=-6\Leftrightarrow-3x=-27\Leftrightarrow x=9\\24:\left(3x-2\right)=-3\Leftrightarrow3x-2=-8\Leftrightarrow3x=-6\Leftrightarrow x=-2\end{matrix}\right.\\-45:5\left(-3-2x\right)=3\Leftrightarrow-15-10x=-15\Leftrightarrow10x=0\Leftrightarrow x=0\end{matrix}\right.\)
a.
\(15-\left(x-7\right)=-21\)
\(x-7=15-\left(-21\right)\)
\(x-7=36\)
\(x=36+7\)
\(x=43\)
b.
\(3x+17=2\)
\(3x=2-17\)
\(3x=-15\)
\(x=-15\div3\)
\(x=-5\)
c.
\(45-\left(x-9\right)=-35\)
\(x-9=45-\left(-35\right)\)
\(x-9=80\)
\(x=80+9\)
\(x=89\)
d.
\(\left(-5\right)+x=15\)
\(x=15-\left(-5\right)\)
\(x=20\)
e.
\(2x-\left(-17\right)=15\)
\(2x=15+\left(-17\right)\)
\(2x=-2\)
\(x=-2\div2\)
\(x=-1\)
g.
\(\left|x-2\right|=3\)
\(x-2=\pm3\)
\(x=3-2\)
\(x=1\)
\(x=-3+2\)
\(x=-1\)
Vậy x = 1 hoặc x = - 1.
Chúc bạn học tốt
a)
15-(x-7)=-21
x-7=15-(-21)
x-7=36
x=36+7
x=43
b)
3x+17=2
3x=17-2
3x=15
x=15:3
x=5
c)
45-(x-9)=-35
x-9=45-(-35)
x-9=80
x=80+9
x=89
d)
(-5)+x=15
x=15-(-5)
x=20
e)
2x-(-17)=15
2x=15+(-17)
2x=-2
x=-2:2
x=-1
g)
TH1
|x-2|=3
x-2=3
x=3+2
x=5
TH2
|x-2|=3
x-2=-3
x=-3+2
x=-1