A)6 và 4/5-(1 và 2/3+3 và 4/5)

=6+4/5-1-2/3-3-4/5

=(6-1-3)+(4/5-4/5)-2/3

=2-2/3=1 và 1/3

B)[(19+5/8/7/12)-(13+1/4/7/12)]X4/5

=[(19-13)+(5/8/7/12-1/4/7/12)]X4/5

=[6+3/8/7/12]X4/5

=[6+9/14]X4/5

=93/14 X4/5=186/35

nhớ

4 và 2/5 + 5 và 6/9 +2 và 3/4 + 3/5+1/3+1/4

= 22/5+51/9+11/4+3/5+1/3+1/4

=(22/5+3/5)+(51/9+1/3)+(11/4+1/4)

=25/5+54/9+12/4

=5+6+3

=14

rút gọn 4/6

\(a.32,5-3\cdot0,87=32,5-2,61=29,89\)

\(8,5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8,5\cdot\left(\dfrac{3}{2}+\dfrac{4}{4}\right):5\\ =8,5\cdot\left(\dfrac{6}{4}+\dfrac{4}{4}\right):5\\ =8,5\cdot\dfrac{10}{4}:5\\ =\dfrac{85}{4}:5\\ =\dfrac{17}{4}\)

\(b.30,96-6,45+14,4:3=30,96-6,45+4,8\\ =29,31\)

\(\dfrac{2}{5}\cdot\left(\dfrac{4}{5}-\dfrac{1}{2}\right)=\dfrac{2}{5}\cdot\left(\dfrac{8}{10}-\dfrac{5}{10}\right)\\ =\dfrac{2}{5}\cdot\dfrac{3}{10}=\dfrac{3}{25}\)

bài 2

\(a.2,5\cdot12,5\cdot8\cdot0,4=\left(2,5\cdot0,4\right)\left(12,5\cdot8\right)\\ =1\cdot100=100\)

b,\(\dfrac{12}{15}\cdot\dfrac{5}{6}\cdot\dfrac{3}{20}\cdot\dfrac{32}{5}=\dfrac{12\cdot5\cdot3\cdot32}{15\cdot6\cdot20\cdot5}\\ =\dfrac{3\cdot4\cdot5\cdot3\cdot4\cdot8}{3\cdot5\cdot2\cdot3\cdot5\cdot4\cdot5}=\dfrac{16}{25}\)

Bài 1: 

a) \(32.5-3\cdot0.87=32.5-2.61=29.89\)

\(8.5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8.5\cdot\dfrac{5}{2}:5=\dfrac{17}{2}\cdot\dfrac{5}{2}:5=\dfrac{85}{4}\cdot\dfrac{1}{5}=\dfrac{17}{4}\)

ta có: \(\hept{\begin{cases}8\frac{3}{4}=\frac{8\times4+3}{4}=\frac{35}{4}\\4\frac{1}{5}=\frac{4\times5+1}{5}=\frac{21}{5}\\3\frac{3}{4}=\frac{3\times4+3}{4}=\frac{15}{4}\end{cases}}\)

2 và 4 phần 5 : 14/5

5 và 1 phần 4 : 21/4

7 và 2 phần 5 : 37/5

4 và 1 phần 25 : 101/25

\(2\frac{4}{5}=2,8\), \(5\frac{1}{4}=5,25\),\(7\frac{2}{5}=7,4\),\(4\frac{1}{25}=4,04\)

So sánh \(\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{2011\times2012}\) với \(\frac{1}{2}\)

\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-...+\frac{1}{2011}-\frac{1}{2012}\)

\(=\frac{1}{2}-\frac{1}{2012}< \frac{1}{2}\)

a) \(\left(8\frac{4}{5}x-50\right):0,4=5\)

\(\Rightarrow\left(\frac{44}{5}x-50\right)=5.0,4\)

\(\Rightarrow\frac{44}{5}x-50=2\)

\(\Rightarrow\frac{44}{5}x=2+50\)

\(\Rightarrow\frac{44}{5}x=52\)

\(\Rightarrow x=\frac{65}{11}\)

b) \(\left(\frac{5x}{3}-3\right):15=\frac{3}{10}\)

\(\Rightarrow\frac{5x}{3}-3=\frac{3}{10}.15\)

\(\Rightarrow\frac{5x}{3}-3=\frac{45}{10}\)

\(\Rightarrow\frac{5x}{3}=\frac{45}{10}+3\)

\(\Rightarrow\frac{5x}{3}=\frac{15}{2}\)

\(\Rightarrow5x.2=3.15\)

=> 5x.2 = 45

=> 5x = 45 : 2

=> 5x = 45/2

=> x = 9/2