+ \(72:\left(x-15\right)=8\)

\(x-15=9\)

\(x=24\)

+ \(\dfrac{3}{90}-3x=3\)

\(3\left(\dfrac{1}{90}-x\right)=3\)

\(\dfrac{1}{90}-x=1\)

\(x=\dfrac{1}{90}-1=\dfrac{-89}{90}\)

Lời giải:

$(x-15)-x.13=0$

$x-15-x.13=0$

$(x-x.13)-15=0$

$x(1-13)-15=0$

$x.(-12)-15=0$

$x.(-12)=15$

$x=15:(-12)=\frac{-5}{4}$

a,  \(0,5x-\frac{2}{3}x=\frac{7}{12}\)

=> \(x\left(0,5-\frac{2}{3}\right)=\frac{7}{12}\)

=>\(\frac{-1}{6}x=\frac{7}{12}\)=> \(x=\frac{7}{12}:\frac{-1}{6}=\frac{-7}{2}\)

b,  \(x:\frac{13}{3}=-2,5\)

=>\(x=\left(-2,5\right):\frac{13}{3}=\frac{-7,5}{13}\)

c,   \(5,5x=\frac{13}{15}\)

=>\(x=\frac{13}{15}:5,5=\frac{13}{82,5}\)

d,  \(\left(\frac{3x}{7}+1\right):\left(-4\right)=\frac{-1}{28}\)

=>\(\left(\frac{3x}{7}+1\right)=\frac{-1}{28}:\left(-4\right)=\frac{1}{7}\)

=>\(\frac{3x}{7}=\frac{1}{7}-1=\frac{-6}{7}\)

=>\(3x=-6\)

=> \(x=\left(-6\right):3=-3\)

cực gấpppppp

1)x=-30

2)x=-81

3)x=4

4)x=62

5)x=6

6)-13

7)-13

8)-31

9)x=-6;0;6;12

tk minh nha

bạn không có lời giải

-7+x = 15

=> x = 15-(-7) = 22

2.x-10 = -26

=> 2.x = -26+10 = -16

=> x = -16 : 2 = -8

|x+7| = 4 

=> x+7=-4 hoặc x+7=4

=> x=-11 hoặc x=-3

(x-9).(3x+6) = 0

=> x-9=0 hoặc 3x+6=0

=> x=9 hoặc x=-2

Tk mk nha

1) Ta có: \(-7+x=15\)

\(\Rightarrow x=15-\left(-7\right)\)

\(\Rightarrow x=22\)

2) \(2x-10=-26\)

\(\Rightarrow2x=-26+10\)

\(\Rightarrow2x=-16\)

\(\Rightarrow x=-8\)

3) \(\left|x+7\right|=4\)

\(\Rightarrow x+7=\pm4\)

Nếu x + 7 = 4 thì x = -3

Nếu x + 7 = -4 thì x = -11

Vậy \(x=\left\{-3;-11\right\}\)

4) \(\left(x-9\right)\left(3x+6\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-9=0\\3x+6=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0+9\\3x=-6\end{cases}\Rightarrow}\orbr{\begin{cases}x=9\\x=-2\end{cases}}}\)

Vậy \(x=\left\{9;-2\right\}\)

c)(x-4).(2x+6)=0

=>(x-4)=0 hoặc (2x+6)=0

với x-4 = 0

      x    =0+4

      x    =4

với 2x+6=0

      2x    =0-6

      2x    =-6

      x      =-6:2

      x      =-3

3x=(-7)+1

3x=(-6)

x=(-6):3

x=(-2)