a) \(\dfrac{7}{9}\times\dfrac{13}{25}\times\dfrac{9}{7}=\left(\dfrac{7}{9}\times\dfrac{9}{7}\right)\times\dfrac{13}{25}=1\times\dfrac{13}{25}=\dfrac{13}{25}\)

b) \(\dfrac{5}{9}\times\dfrac{21}{25}+\dfrac{21}{25}\times\dfrac{4}{9}\)

\(=\dfrac{21}{25}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)\)

\(=\dfrac{21}{25}\times1=\dfrac{21}{25}\)

c) \(\dfrac{19}{5}\times\dfrac{11}{16}-\dfrac{9}{5}\times\dfrac{11}{16}\)

\(=\dfrac{11}{16}\times\left(\dfrac{19}{5}-\dfrac{9}{5}\right)\)

\(=\dfrac{11}{16}\times2=\dfrac{22}{16}=\dfrac{11}{8}\)

Giải chi tiết cho mình nha

2/5 + 11/15 = 17/15
7/8 - 7/9 = 7/72
11/13 x 26/31 = 22/31
16/24 : 4 = 1/6
30 : 6/5 = 25
9/16 : 4 = 9/64
1/2 : 1/3 x 8/15 = 3/2 x 8/15 = 4/5

a , \(\frac{5}{7}\)\(+\)\(\frac{3}{4}\)\(=\)\(\frac{41}{28}\)

b, \(\frac{5}{9}\)\(+\)\(\frac{6}{9}\)X \(\frac{3}{11}\)\(=\)\(\frac{73}{99}\)

các bạn giải cách làm hộ mình với

X-3/11=11/13

         =11/13+3/11

         =160/143

9/11+x=14/15

          =14/15-9/11

          =19/165

nếu sai thì thôi bỏ wa cho mik nhá!!

    x - 3/11 = 11/13

    x          = 11/13 + 3/11

    x          =     160/143

    9/11 + x = 14/15

              x = 14/15 - 9/11

              x =     19/165

mn giúp mình nha mình cần đáp án ngay bây giờ

câu a bằng 15/8

câu b bằng 19/6

câu c bằng 3/10

câu d bằng 27/4

v

???

a.11/7.8/13+8/13.3/7+8/13

=8/13.(11/7+3/7+1)

=8/13.3

=24/13

b.5/7.8/13+8/13.9/7-8/13

=8/13.(5/7+9/7-1)

=8/13.1

=8/13

c.157.199-56.199-199

=199.(157-56-1)

=199.100

19900

\(a.18\times85+9\times30\)

\(\text{=}1530+270\)

\(\text{=}1800\)

\(b.9\times13+9\times80+63\)

\(\text{=}117+720+63\)

\(\text{=}900\)

\(c.8\times11+16\times40+72\)

\(\text{=}88+640+72\)

\(\text{=}800\)

a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)

   = \(\frac{11}{21}\)x 3

  = \(\frac{33}{21}\)

b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)

    = 1 x \(\frac{6}{13}\)

    = \(\frac{6}{13}\)

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a: =11/4+5/4-9/8

=4-9/8=32/8-9/8=23/8

b: \(=\dfrac{6}{7}\cdot\dfrac{7}{4}+\dfrac{5}{3}=\dfrac{3}{2}+\dfrac{5}{3}=\dfrac{9+10}{6}=\dfrac{19}{6}\)

c: \(=\dfrac{13}{18}\cdot\dfrac{9}{5}-1=\dfrac{13}{10}-1=\dfrac{3}{10}\)

d: \(=3+\dfrac{9}{4}\cdot\dfrac{5}{3}=3+\dfrac{45}{12}=\dfrac{81}{12}=\dfrac{27}{4}\)

`a)11/4+5/4-9/8=4-9/8=32/8-9/8=23/8`

`b)6/7 xx 7/4+5/3=3/2+5/3=9/6+10/6=19/6`

`c)13/18xx9/5−1=13/10−1=3/10`

`d)3+9/4xx5/3=3+45/12=27/4`