Kết quả là 0,18 nhé bạn

Mình cần đáp án bạn ơi

Đây là môn Ngoại Ngữ ạ!!!
 

= -125.40.64/135.16384.(-1)

= 5.(-25).5.8.64/5.27.64.8.32.(-1)

= -25.5/27.32.(-1)

= 25.5/27.32

= 125/864

\(a,\dfrac{2}{3}+\dfrac{1}{3}\times x^2=\left(-2\right)^0\)

\(\dfrac{2}{3}+\dfrac{1}{3}\times x^2=1\)

\(\dfrac{1}{3}\times x^2=1-\dfrac{2}{3}\)

\(\dfrac{1}{3}\times x^2=\dfrac{1}{3}\)

\(x^2=\dfrac{1}{3}:\dfrac{1}{3}\)

\(x^2=1\)

\(\Rightarrow x=\pm1\)

\(\dfrac{2}{3}+\dfrac{1}{3}.x^2=\left(-2\right)^0\)

\(\Leftrightarrow\dfrac{1}{3}.x^2=1-\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{1}{3}x^2=\dfrac{1}{3}\)

\(\Leftrightarrow x^2=1\)

\(\Leftrightarrow\left|x\right|=1\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\end{matrix}\right.\)

a: =-5/7(2/11+9/11)+12/7

=12/7-5/7

=7/7=1

b: \(=\dfrac{-12}{56}+\dfrac{35}{56}-\dfrac{28}{56}=\dfrac{-5}{56}\)

c: \(=\dfrac{1}{4}-\dfrac{5}{13}+\dfrac{2}{11}-\dfrac{8}{13}+\dfrac{3}{4}\)

=1-1+2/11

=2/11

d: \(=\dfrac{21}{31}+\dfrac{-16}{7}+\dfrac{44}{53}+\dfrac{10}{31}+\dfrac{9}{53}\)

=1+1-16/7

=-2/7

e: \(=\dfrac{\dfrac{4}{36}-\dfrac{30}{36}-\dfrac{144}{36}}{\dfrac{21}{36}-\dfrac{1}{36}-\dfrac{360}{36}}=\dfrac{-160}{-340}=\dfrac{8}{17}\)

a) −512−512 . 419419 +−712−712 . 419419 -40574057 Đầu tiên, chúng ta tính toán phép nhân: −512 x 419419 = -214,748,928 −712 x 419419 = -298,238,328

Tiếp theo, chúng ta tính tổng của hai kết quả: -214,748,928 + -298,238,328 = -513,987,256

Cuối cùng, chúng ta trừ đi 40574057: -513,987,256 - 40574057 = -554,561,313

Vậy kết quả của phép tính a là -554,561,313.

b) 1313 . 4545 + 1313.1.1515 + ( −32−32 )^2 Đầu tiên, chúng ta tính toán phép nhân: 1313 x 4545 = 5,964,385 1313 x 1.1515 = 1,511.195 −32 x −32 = 1,024

Tiếp theo, chúng ta tính tổng của ba kết quả: 5,964,385 + 1,511.195 + 1,024 = 5,966,920.195

Vậy kết quả của phép tính b là 5,966,920.195.

\(c`3,4.0,7+3,4.0,3-0,4=3,4.\left(0,7+0,3\right)-0,4=3,4.10-0,4=34-0,4=33,6\)

\(d`\left(1-\dfrac{1}{2}+\dfrac{3}{4}\right)-\left(\dfrac{1}{2}+1\dfrac{3}{4}-3\right)=\left(1-\dfrac{1}{2}+\dfrac{3}{4}\right)-\left(\dfrac{1}{2}+\dfrac{7}{4}-3\right)=1-\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{2}-\dfrac{7}{4}+3=\left(1+3\right)+\left(-\dfrac{1}{2}-\dfrac{1}{2}\right)+\left(\dfrac{3}{4}-\dfrac{7}{4}\right)=4+\left(-1\right)+\left(-1\right)=2\)

\(c)\)\(\left(-\dfrac{1}{2}\right)^3:1\dfrac{3}{8}-25\%\cdot\left(-6\dfrac{2}{11}\right)\)

\(=-\dfrac{1}{8}\cdot\dfrac{8}{11}-\dfrac{1}{4}\cdot\left(-\dfrac{68}{11}\right)\)

\(=-\dfrac{1}{11}+\dfrac{17}{11}\)

\(=\dfrac{16}{11}\)

#Ayumu

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IX.

1.. the toystore is to the left of the restaurant. RIGHT

the restaurant is to the right of the toystore

2. the hospital is behid the museum . FRONT

the museum is in front of the hospital

3. there is a small garden in my school . HAS

my school has a small garden

4. david's house isn't far from the station . NEAR

David's house is near the station

5. the bookstore is to the left of the toystore and to the right of the police station . BETWEEN

the bookstore is between the toystore and the police station

1. The toystore is to te left of the restaurant (RIGHT)

\(\Rightarrow\)The restaurant is to the right of the toystore.

2. The hospital is behind the museum (FRONT)

\(\Rightarrow\)The museum is frontof the hospital.

3. There is a small garden in my school (HAS)

\(\Rightarrow\)My school has a small garden.

4. David's house isn't far from the station (NEAR)

\(\Rightarrow\)David's house is near the station.

5. The bookstore is to the left of the toystore and to the right of the police station (BETWEEN)

\(\Rightarrow\)The bookstore is between the toystore and the police station.