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a ( 1+2+3+4+....+99)*(13*15-12*25-15)
= ( 1+2+3+4+....+99)*[15*(13-1)-12*25)]
=( 1+2+3+4+....+99)*[15*12-12*25]
=( 1+2+3+4+....+99)*[12*(15-25)]
=( 1+2+3+4+....+99)*[12*(-10)]
=( 1+2+3+4+....+99)*(-120)
= -594000
b 3*5*36+15+42+30*11
=15*36+15*1+42+15*22
=15*(36+1+22)+42
=15*59+42
=885+42
=927
Tick cho mk nha
a. ( 1+2+3+4+....+99)*(13*15-12*25-15)
=( 1+2+3+4+....+99) . 0
=0
b 3*5*36+15+42+30*11
=540 + 15 +42 + 330
=927
\(=\dfrac{8}{15}\left(\dfrac{25}{32}-\dfrac{10}{32}\right)=\dfrac{8}{15}\cdot\dfrac{15}{32}=\dfrac{1}{4}\)
=15/17 x (4/7 + 3/7) - 1/3
=15/17 x 1 - 1/3
=15/17 x (3/3 - 1/3)
=15/17 x 2/3
=30/51
3 \(\times\) \(\dfrac{4}{15}\) + 2 \(\times\) \(\dfrac{4}{15}\) - 5 \(\times\) \(\dfrac{4}{15}\)
= \(\dfrac{4}{15}\) \(\times\) ( 3 + 2 - 5)
= \(\dfrac{4}{15}\) \(\times\) 0
= 0
\(\dfrac{3}{12}\)x\(\dfrac{15}{6}\)x\(\dfrac{8}{5}\)
=> \(\dfrac{5}{8}\)x\(\dfrac{8}{5}\)
=>1
Bài làm
\(\frac{7}{15}x\frac{3}{8}+\frac{7}{15}x\frac{5}{8}\)
= \(\frac{7}{15}x\left(\frac{3}{8}+\frac{5}{8}\right)\)
= \(\frac{7}{15}x\frac{8}{8}\)
= \(\frac{7}{15}x1\)
= \(\frac{7}{15}\)
# Chúc bạn học tốt #
\(\frac{7}{15}\cdot\frac{3}{8}+\frac{7}{15}\cdot\frac{5}{8}\)
\(=\frac{7}{15}\cdot(\frac{3}{8}+\frac{5}{8})\)
\(=\frac{7}{15}\cdot1=\frac{7}{15}\)
\(99\times36+57\times99+99-84\times99\)
\(=99\times(36+57+1-84)\)
\(=99\times10=990\)
99 x 36 + 57 x 99 - 84 x 99
= 99 x ( 36 + 57 + 1 - 84 )
= 99 x 10
= 990
99 x 15 + 15 = 15 x ( 99 + 1) = 15 x 100 = 1500