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a) \(\dfrac{81\times49}{7\times8}=\dfrac{81\times7\times7}{7\times8}=\dfrac{81\times7}{8}=\dfrac{567}{8}\)
b) \(\dfrac{105\times69}{3\times35}=\dfrac{3\times35\times69}{3\times35}=69\)
c) \(\dfrac{77\times39}{13\times11}=\dfrac{11\times7\times13\times3}{13\times11}=7\times3=21\)
a) \(\dfrac{81x49}{7x8}=\dfrac{81x7x7}{7x8}=\dfrac{81x7}{8}=\dfrac{567}{8}=70,875\)
b) \(\dfrac{105x69}{3x35}=\dfrac{3x35x69}{3x35}=\dfrac{69}{1}=69\)
c) \(\dfrac{77x39}{13x11}=\dfrac{11x7x3x13}{13x11}=\dfrac{7x3}{1}=\dfrac{21}{1}=21\)
Giải nè!:
a) =72/99 - 14/99 - 28/99= 30/99=10/33
b) = 83,45 - (30,98+42,47) = 83,45 - 73,45 = 10
Tích đúng cho tớ nè!
a) \(\frac{14}{15}+\frac{3}{11}+\frac{1}{15}+\frac{3}{11}+\frac{10}{22}\)
\(=\left(\frac{14}{15}+\frac{1}{15}\right)+\left(\frac{3}{11}+\frac{3}{11}\right)+\frac{10}{22}\)
\(=1+1+\frac{10}{22}\)
\(=2+\frac{10}{22}\)
\(=\frac{27}{11}\)
b) 9,25 + 9,25 x 8 + 9,25
= 9,25 x ( 8 + 1 + 1 )
= 9,25 x 10
= 92,5
a) \(\frac{8}{11}-\frac{28}{99}-\frac{14}{99}=\frac{72}{99}-\frac{28}{99}-\frac{14}{99}=\frac{30}{99}=\frac{10}{33}\)
b) \(5\frac{3}{4}-3\frac{1}{2}=\)\(\frac{23}{4}-\frac{7}{2}=\frac{23}{4}-\frac{14}{4}=\frac{9}{4}\)
A) 8/11- 28/99- 14/99 8/11=72/99 (72/99 +28/99)-14/99 =100/99-14/99 =86/99
27/8 - 7/3 + 4/3 - 2
= 27/8 - (7/3 - 4/3) - 2
= 27/8 - 1 - 2
=27/8 - 3
= 3/8
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a \(\frac{4}{18}+\frac{5}{13}+\frac{7}{9}+\frac{21}{13}\)
= \(\left(\frac{4}{18}+\frac{7}{9}\right)+\left(\frac{5}{13}+\frac{21}{13}\right)\)
= \(1+2\)
= \(3\)
b \(\frac{4}{3}-\frac{2}{7}-\frac{5}{7}+\frac{2}{3}\)
= \(\left(\frac{4}{3}-\frac{2}{3}\right)-\left(\frac{2}{7}+\frac{5}{7}\right)\)
= \(\frac{2}{3}-1\)
= \(-\frac{1}{3}\)
Dễ mà bạn cũng ko biết sao để mình giải cho
0,25 + 9998 +4/5+1/5+3/4
= 1/4+9998+4/5+1/5+3/4
=(1/4+3/4)+(4/5+1/5)+9998
=1+1+9998
=2+9998
=10000
Nhớ k và ấn đúng cho mình nhé !
Lần sau khó mình giúp tiếp cho
\(\frac{10x18}{27x25}\) = \(\frac{2x5x2x3x3}{3x3x3x5x5}\) = \(\frac{4}{15}\)