c bn

chúc bạn học tốt

TL:

a)25 x 12 x 30 x 4 

= (25 x 5) x (12 x 30)

= 100 x 360

= 36000

b)23 + 23 x 2 + 23 x 3 +23 x 4 

= 23 x 1 + 23 x 2 + 23 x 3 +23 x 4

= 23 x (1 + 2 + 3 + 4)

= 23 x 10

= 230

c)248 x 2005 - 2005 x 148

= (248 - 148) x 2005

= 100 x 2005

= 200500

HT

TL: 

8/15 x 5/6 = 40/90 = 4/9 

41/20 x 3/4 = 123/80 

(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43 

HT

\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)

\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)

\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)

/HT\

TL

\(\frac{7}{8}\)+\(\frac{4}{23}\)+\(\frac{42}{23}\)=\(\frac{7}{8}+2\)=\(\frac{23}{8}\)

nha bn

HT

\(TL:\)

\(\frac{7}{8}+\frac{4}{23}+\frac{42}{23}\)

\(=\frac{7}{8}+\left(\frac{4}{23}+\frac{42}{23}\right)\)

\(=\frac{7}{8}+\frac{46}{23}\)

\(=\frac{7}{8}+2\)

\(=\frac{7}{8}+\frac{16}{8}\)

\(=\frac{23}{8}\)

\(=2\frac{7}{8}\)

\(HT!\)

\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}=\frac{19-4}{15}+\frac{31-8}{23}=\frac{15}{15}+\frac{23}{23}=1+1=2\)

\(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)

\(=\frac{19-4}{15}+\frac{31-8}{23}\)

\(=\frac{15}{15}+\frac{23}{23}\)

\(=1+1=2\)

567 x 23 + 433 x 23 = 23 x (567 + 433)

                                 =23 x 1000 = 23 000

a)Vì có nhiều số 52 nên .52x(3+7)=52x10=520

b)Vì có nhiều số 23 nên.23x(2+6+2)=23x10=230

c)Vì  số 64 phép cuối ko có số nhân nên ta coi số đó là 1 nên. 64x7+64x2+64x1=64x(7+2+1)=64x10=640

d)Vì phép tính ở giữa có 2 số 48 cộng nên ta coi đó là 1 nên.48x(3+6+1)=48x10=480

nhé

a) 52 x 7 + 52 x 3 

= 52 x ( 7 + 3 ) 

= 52 x 10 

= 520

b) 23 x 2 + 6 x 23 + 23 x 2 

= 23 x ( 2 + 6 + 2 )

= 23 x 10

= 230

c) 64 x 7 + 64 x 2 + 64 

= 64 x 7 + 64 x 2 + 64 x 1 

= 64 x ( 7 + 2 + 1 ) 

= 64 x 10 

= 640

d) 48 x 3 + 48 + 48 x 6 

 = 48 x 3 + 48 x 1 + 48 x 6 

 = 48 x ( 3 + 1 + 6 )

= 48 x 10

= 480

\(\dfrac{11}{34}+\dfrac{5}{23}+\dfrac{23}{34}+\dfrac{18}{23}\)
\(=\left(\dfrac{11}{34}+\dfrac{23}{34}\right)+\left(\dfrac{5}{23}+\dfrac{18}{23}\right)\)
\(=1+1\)
\(=2\)
#DatNe

=2

TL:

\(\text{567 x 23 + 433 x 23}\)

\(=\left(567+433\right) x 23\)

\(=1000x 23\)

\(=23000\)

HT

a) \(\frac{7}{18}+\frac{4}{23}+\frac{11}{18}+\frac{19}{23}\)

\(=\left(\frac{7}{18}+\frac{11}{18}\right)+\left(\frac{4}{23}+\frac{19}{23}\right)\)

\(=1+1\)

\(=2\)

b) \(\frac{19}{15}+\frac{31}{23}-\frac{4}{15}-\frac{8}{23}\)

\(=\left(\frac{19}{15}-\frac{4}{15}\right)+\left(\frac{31}{23}-\frac{8}{23}\right)\)

\(=1+1\)

\(=2\)

ủng hộ tớ nha

a) (7/18+11/18)+(4/23+19/23)

=18/18+23/23

=1+1

=2

b)=2