\(\left(2\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}=3+\frac{1}{6}=3\frac{1}{6}\)

Đầu tiên bạn chuyển cái j ý nhỉ .. xang phân số mà ta lại thấy cái phân số có có mẫu số chung với ps 3/5

Ta nhóm lại rùi cộng với phân số 3/5

a) $\frac{2}{7}:\frac{4}{9} = \frac{2}{7} \times \frac{9}{4}$                     

b) $\frac{{12}}{{25}}:\frac{6}{5} = \frac{{12}}{{25}} \times \frac{5}{6}$   

c) $\frac{5}{8}:3 = \frac{5}{8}:\frac{3}{1} = \frac{5}{8} \times \frac{1}{3}$

giúp với ạ

giải dc nhưng mà hoi lâu

a) \(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)

= \(\left(\frac{12}{25}+\frac{13}{25}\right)+\frac{3}{5}\)

= \(\frac{25}{25}+\frac{3}{5}\)

= \(1+\frac{3}{5}\)

= \(\frac{1}{1}+\frac{3}{5}\)

= \(\frac{5}{5}+\frac{3}{5}\)

= \(\frac{8}{5}\)

bài này tớ mà làm sai thì tớ ......................ko lm người........-_-

a) \(\frac{12}{25}+\frac{3}{5}+\frac{13}{25}\)

= \(\frac{12}{25}+\frac{15}{25}+\frac{13}{25}\)

= \(\frac{12+15+13}{25}\)

= \(\frac{40}{25}\)

= \(\frac{8}{5}\)

b) \(\frac{3}{2}+\frac{2}{3}+\frac{4}{3}\)

= \(\frac{9}{6}+\frac{4}{6}+\frac{8}{6}\)

= \(\frac{9+4+8}{6}\)

= \(\frac{21}{6}\)

= \(\frac{7}{2}\)

12/5 -4/5 =8/5

11/6 -2/3 =21/18 =7/6

7/8 -2/7 =33/56

4 -8/5 =20/5-8/5 =12/5

2 -3/8 =16/8 -3/8 =13/8

16/7 -2 =16/7 -14/7 =2/7

25/4 -3=25/4 -12/4 =13/4

câu 2 :                                       câu 3 :

a) 8/5                                         a)4 - 8/5 = 20/5 - 8/5 =12/5

b) 7/6                                         b)2 - 3/8 =16/8 - 3/8 = 13/8 

c) 35/56                                      c)16/7 - 2 = 16/7 - 14/7 = 2/7

                                                  d)25/4 - 3 = 25/4 - 12/4 = 13/4

a) $\frac{1}{2} - \frac{1}{4} = \frac{2}{4} - \frac{1}{4} = \frac{1}{4}$   

b) $\frac{2}{3} - \frac{4}{{15}} = \frac{{10}}{{15}} - \frac{4}{{15}} = \frac{6}{{15}} = \frac{2}{5}$                       

c) $\frac{3}{5} - \frac{{10}}{{25}} = \frac{{15}}{{25}} - \frac{{10}}{{25}} = \frac{5}{{25}} = \frac{1}{5}$

a) $\frac{4}{{25}}:\frac{4}{3} = \frac{4}{{25}} \times \frac{3}{4} = \frac{3}{{25}}$ 

b) $\frac{3}{{14}}:\frac{6}{7} = \frac{3}{{14}} \times \frac{7}{6} = \frac{{3 \times 7}}{{14 \times 6}} = \frac{{3 \times 7}}{{7 \times 2 \times 3 \times 2}} = \frac{1}{4}$

c) $\frac{{12}}{{15}}:2 = \frac{{12}}{{15}} \times \frac{1}{2} = \frac{{12 \times 1}}{{15 \times 2}} = \frac{{6 \times 2 \times 1}}{{15 \times 2}} = \frac{6}{{15}}$           

d) $\frac{{21}}{8}:6 = \frac{{21}}{8} \times \frac{1}{6} = \frac{{21 \times 1}}{{8 \times 6}} = \frac{{7 \times 3 \times 1}}{{8 \times 3 \times 2}} = \frac{7}{{16}}$

Mình sửa lại đề xíu.

a) \(\frac{75}{100}+\frac{18}{21}+\frac{19}{32}+\frac{1}{4}+\frac{3}{21}+\frac{13}{32}=\frac{3}{4}+\frac{1}{4}+\frac{18}{21}+\frac{3}{21}+\frac{19}{32}+\frac{13}{32}=1+1+1=3\)

b) \(4\frac{2}{5}+5\frac{6}{9}+2\frac{3}{4}+\frac{3}{5}+\frac{1}{3}+\frac{1}{4}=4+\frac{2}{5}+\frac{3}{5}+5+\frac{2}{3}+\frac{1}{3}+2+\frac{3}{4}+\frac{1}{4}\)

\(=4+1+5+1+2+1=14.\)

c) \(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+...+\frac{2}{41\cdot43}=\frac{5-3}{3\cdot5}+\frac{7-5}{5\cdot7}+\frac{9-7}{7\cdot9}+...+\frac{43-41}{41\cdot43}\)

\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{41}-\frac{1}{43}=\frac{1}{3}-\frac{1}{43}=\frac{43-3}{3\cdot43}=\frac{40}{129}.\)

a Đ

b S

c S

d Đ

a ) S 

b ) Đ

c ) S

d ) Đ

k cho mk nhé