\(\frac{11.3^{22}.3^8-9^{15}}{\left(2.3^{14}\right)^2}=\frac{45}{2}\) Nhé

Tk mình nha

\(\frac{45}{2}\) nhé !

Học tốt !

\(\frac{11.3^{32}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{39}-3^{30}}{4.3^{28}}=\frac{3^{30}.\left(11.3^9-1\right)}{4.3^{28}}=\frac{9.\left(11.3^9-1\right)}{4}=487152\)

\(A=\frac{11.3^{22}.3^7.9^{15}}{\left(2.3^{14}\right)^2}\)

\(A=\frac{11.3^{29}-3^{30}}{2^2.\left(3^{14}\right)^2}\)

\(A=\frac{3^{29}.\left(11-3\right)}{2^2.3^{28}}\)

\(A=\frac{3.2}{1.1}\)

\(A=\frac{6}{1}\)

\(A=6\)

\(a=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{29}-\left(3^2\right)^{15}}{\left(2^2.3^{28}\right)}=\frac{11.3^{29}-3.^{30}}{2^2.328}\)

\(=\frac{3^{28}\left(11.3-3^2\right)}{2^2.3^{28}}=\frac{33-9}{4}=6\)

Bài 35 :

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(A=\frac{2^{10}.\left(13+65\right)}{2^8.104}\)

\(A=\frac{2^8.2^2.98}{2^8.104}\)

\(A=\frac{2^8.4.98}{2^8.4.26}\)

\(A=\frac{49}{13}\)

Vậy \(A=\frac{49}{13}\)

\(B=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(B=\frac{11.3^{29}-9^{15}}{2^2.\left(3^{14}\right)^2}\)

\(B=\frac{11.3^{29}-9^{15}}{2^2.3^{28}}\)

\(B=\frac{11.3^{29}-\left(3^2\right)^{15}}{4.3^{28}}\)

\(B=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)

\(B=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)

\(B=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)

\(B=\frac{3^{29}.8}{4.3^{28}}\)

\(B=\frac{3^{28}.3.4.2}{4.3^{28}}\)

\(B=3.2\)

\(B=6\)

Vậy B = 6 

A = 2^10 . 13 + 2^10 . 65 / 2^8 . 104

   = 2^10 ( 13 + 65 ) / 2^8 . 104 = 2^10 . 78 / 2^8 . 104 = 2^8 . 2^2 . 78 / 2^8 . 104 = 2^8 . 4 . 78 / 2^8 . 104 = 2^8 . 312 / 2^8 . 104

   = 312/104

   = 3

B = 11 . 3^22 . 3^7 - 9^15 / ( 2.3^14)^2

   = 11 . 3^29 - (3^2)^15 / ( 3.2^14)^2

   = 11 . 3^29 - 3^30 / ( 3. 2 )^28

    = ( 8 + 3 ) . 3^29 - 3^30 / ( 3. 2)^28

    = 8 . 3^29 + 3.3^29 - 3^30 / ( 3.2)^28

     = 8 . 3^29 + 3^30 - 3^30 / ( 3 . 2)^28

    = 8 . 3^29 / 3^28 . 2^28

     = 2^3 . 3 / 2^28

     = 3/ 2^25

\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

\(A=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{28}}\)

\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)

\(A=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}\)

\(A=\frac{3^{29}.8}{4.3^{28}}=3.2=6\)

Ta có: \(A=\dfrac{5\cdot\left(2^2\cdot3^2\right)^9\cdot\left(2^2\right)^6-2\cdot\left(2^2\cdot3\right)^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{5\cdot2^{18}\cdot3^{18}\cdot2^{12}-2\cdot2^{28}\cdot3^{14}\cdot3^4}{5\cdot2^{28}\cdot3^{18}-7\cdot2^{28}\cdot3^{18}\cdot2}\)

\(=\dfrac{5\cdot2^{30}\cdot3^{18}-2\cdot2^{28}\cdot3^{18}}{2^{28}\cdot3^{18}\cdot\left(5-7\cdot2\right)}\)

\(=\dfrac{2^{28}\cdot3^{18}\cdot\left(5\cdot2^2-2\right)}{2^{28}\cdot3^{18}\cdot\left(5-14\right)}\)

\(=\dfrac{20-2}{-9}=\dfrac{18}{-9}=-2\)