\(A=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03\)

\(A=\left(9,375+7,625\right)+4,03\)

\(A=17+4,03\)

\(A=21,03\)

\(A=\left(9+\frac{30303}{80808}+7+\frac{303030}{484848}\right)+4,03\)

\(A=\left(9+\frac{3\times10101}{8\times10101}+7+\frac{30\times10101}{48\times10101}\right)+4,03\)

\(A=\left(9+\frac{3}{8}+7+\frac{5}{8}\right)+4,03\)

\(A=\left(9+7+\frac{3}{8}+\frac{5}{8}\right)+4,03\)

\(A=\left(16+1\right)+4,03\)

\(A=17+4,03=21,03\)

H = (9/30303/80808+7/303030/484848)+4,03

   = ( \(\frac{75}{8}+\frac{61}{8}\)) + \(\frac{403}{100}\)

   = \(\frac{136}{8}\)+ \(\frac{403}{100}\)

   =  17 + \(\frac{403}{100}\)

   =  \(\frac{2103}{100}\)

Vậy : H = \(\frac{2103}{100}\)

#Chúc bạn học tốt !

\(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\right).\frac{15}{78}=\left(\frac{39}{4}.40\right).\frac{15}{78}=390.\frac{15}{78}=75\)\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03=\left(9\frac{3}{8}+7\frac{30}{48}\right)+4,03=17+4,03=21,03\)

I=10101(5/111111+5/222222+4/3.7.11.13.37)

I=10101(5/111111+5/222222+4/111111)

I=10101(10/222222+5/222222+8/222222)

I=10101.23/222222

I=232323/222222

\(I=\frac{7}{22}\)

\(H=\frac{2103}{100}=21,03\)

Nhiều bài quá không có thời gian để làm. Thôi thì làm bài dễ nhất vậy.

I = 10101.(5/111111+5/222222-4/3.7.11.13.17)

I = 10101.(5/111111+5/2.111111-4/111111)

I = 10101.10+5-8/222222

I = 10101.7/222222

I = 7/22 

=3/8+5/8=1