Sửa đề : \(10.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)

\(10\cdot\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)

\(=10\cdot\frac{2^{12}\cdot3^{10}+2\cdot9\cdot3^9\cdot2^3\cdot3\cdot5}{2^{12}.3^{12}-2^{11}.3^{11}}\)

\(=10\cdot\frac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{2^{11}\cdot3^{11}\cdot\left(2\cdot3-1\right)}\)

\(=10\cdot\frac{2\cdot6}{3\cdot5}=8\)

........... là gì vậy

trrertre

\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}.10=\frac{2^{12}.3^{10}+2^9.3^9.120}{2^{12}.3^{12}-2^{11}.3^{11}}.10=\frac{2^{10}.3^{10}\left(2^2+20\right)}{2^{10}.3^{10}\left(6^2-6\right)}.10=\frac{24.10}{30}=8\)

10.4⁶.9⁵+6⁹.120 :; 8⁴.3¹²-6¹¹

giúp mk với

bài này khó quá!

giúp nha

thanks

Đầu tiên ta rút gọn \(\frac{4^{^6}.9^{^5}+6^{^9}.120}{8^{^4}.3^{^{12}}-6^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}+2^{^9}.3^{^9}.2^{^3}.3.5}{2^{^{12}}.3^{^{12}}-2^{^{11}}-3^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}+2^{^{12}}.3^{^{10}}.5}{2^{^{12}}.3^{^{12}}-2^{^{11}}.3^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}.\left(1+5\right)}{2^{^{11}}.3^{^{11}}.\left(6-1\right)}\)= \(\frac{2.6}{3.5}\)= \(\frac{12}{15}\)= \(\frac{4}{5}\)

\(\Rightarrow\)10 . \(\frac{4}{5}\)= \(\frac{40}{5}\)= 8

\(A=\frac{\left(2^2\right)^6\cdot\left(3^2\right)^5+6^9\cdot120}{\left(2^3\right)^4\cdot3^{12}-6^{11}}\)

\(A=\frac{2^{12}\cdot3^{10}+6^9\cdot120}{2^{12}\cdot3^{12}-6^{11}}\)

\(A=\frac{1\cdot1+1\cdot120}{1\cdot3^2-6^2}\)(Ở BƯỚC NÀY MÌNH RÚT GỌN TỰ VỚI MẪU VÌ HAI SỐ CÙNG CƠ SỐ)

\(A=\frac{1+120}{1\cdot9-36}\)

\(A=\frac{121}{9-36}\)

\(A=\frac{121}{-27}=-\frac{121}{27}\)

NHỚ NHA