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\(a,=\dfrac{3^6\cdot5^4\cdot9^4-5^{13}\cdot3^{13}\cdot5^{-9}}{3^{12}\cdot5^6+9^6\cdot5^6}=\dfrac{3^{14}\cdot5^4-5^4\cdot3^{13}}{3^{12}\cdot5^6+3^{12}\cdot5^6}\\ =\dfrac{3^{13}\cdot5^4\cdot2}{2\cdot3^{12}\cdot5^6}=\dfrac{3}{5^2}=\dfrac{3}{25}\)
\(b,=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}\cdot\dfrac{16}{3}\right)^3}{2^7\cdot5^2+2^9}=\dfrac{2^7+12^3}{2^7\left(5^2+2^2\right)}=\dfrac{2^7+4^3\cdot3^3}{2^7\cdot29}=\dfrac{2^6\left(2+3^3\right)}{2^7\cdot29}=\dfrac{1}{2}\)
Sửa đề: (2/7)^7*7^7
\(A=\dfrac{\left(2\right)^7+\left(\dfrac{9}{3}:\dfrac{3}{16}\right)^3}{2^7\left(5^2+2^2\right)}\)
\(=\dfrac{\left(2\right)^7+\left(16\right)^3}{2^7\cdot29}\)
\(=\dfrac{2^7+2^7\cdot2^5}{2^7\cdot29}=\dfrac{1+2^5}{29}=\dfrac{33}{29}\)
\(A=\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\\ A=\dfrac{128+1728}{153+512}\\ A=\dfrac{1856}{665}=2\dfrac{526}{665}\)
Chúc bạn học tốt!!!
\(\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7+5^2+512}\)
\(A=\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\)
\(A=\dfrac{128+1728}{153+512}\)
\(A=\dfrac{1856}{665}\)
\(A=2\dfrac{526}{665}\)
Bài 1:
\(\dfrac{\left(\dfrac{2}{5}\right)^7\cdot5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(=\dfrac{\left(\dfrac{2}{5}\cdot5\right)^7+\left(\dfrac{9}{4}:\dfrac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(=\dfrac{2^7+12^3}{2^7\cdot5^2+512}\)
\(=\dfrac{1856}{3712}\)
\(=0,5\)
Bài 2:
\(\left(5x+1\right)^2=\dfrac{36}{49}\)
\(\Rightarrow5x+1=\dfrac{6}{7}\)
\(\Rightarrow5x=\dfrac{-1}{7}\)
\(\Rightarrow x=\dfrac{-1}{35}\)
Bạn đổi \(\left(\frac{2}{5}\right)^7.5^7=\frac{2^7}{5^7}.5^7=2^7=128\)
\(\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3=\frac{9^3}{4^3}.\frac{16^3}{3^3}=\frac{3^3.3^3}{4^3}.\frac{4^3.4^3}{3^3}=3^3.4^3=17.64=1088\)
CỘNG 2 CÁI ĐÓ LẠI RỒI LÀM Ở TỬ SỐ LÀ RA.
BẤM ĐÚNG NẾU THẤY ĐÚNG
\(=\frac{\left(\frac{2}{5}.5\right)^7+\left(\frac{9}{4}:\frac{3}{16}\right)^3}{2^7.5^2+512}=\frac{2^7+12^3}{2^7.5^2+512}=\frac{128+1728}{3200+512}=\frac{1856}{3712}=\frac{1}{2}\)
Ta có:
\(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3\div\left(\dfrac{3}{16}\right)^3}{2^7.5^7+512}\)
=\(\dfrac{\left(\dfrac{2}{5}.5\right)^7+\left(\dfrac{9.16}{4.3}\right)^3}{2^7.5^7+2^9}\)=\(\dfrac{2^7+12^3}{2^7.5^7+2^9}\)=\(\dfrac{2^7+2^6.3^3}{2^7.5^7+2^9}\)
=\(\dfrac{2^6.\left(2+3^3\right)}{2^6.\left(2.5^7+2^3\right)}\)=\(\dfrac{29}{156258}\).
Hì hì sai ko bít nha