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Bài 1:
\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)
\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)
\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)
\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)
\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)
\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)
\(A=\frac{9}{11}\)
Bài 2 :
2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15
Mẫu số = 11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x 17 = (1+27+125+729) x 13 x 15 x 17
\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)
\(=\frac{11}{17}\)
\(=\frac{1111}{1717}=B\)
Vậy \(A=B\)
ta có : 1/5+1/15=1-1/15=14/15
vậy 1/5+1/15+1/45+1/135+1/405=1-1/405=404/405
404/405 NHỚ **** ĐÓ
1)\(A=\frac{1}{3}+\frac{1}{6}+...+\frac{1}{55}=2\left(\frac{1}{6}+\frac{1}{12}+...+\frac{1}{110}\right)=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{10}-\frac{1}{11}\right)=2.\left(\frac{1}{2}-\frac{1}{11}\right)=\frac{9}{11}\)
2) Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15
Mẫu số = 11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17
lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17
= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x 17 = (1+27+125+729) x 13 x 15 x 17
=> \(A
a) 5/30+15/90+25/150+35/210+45/270
=1/6+1/6+1/6+1/6+1/6
=1/6 x 5
=5/6
b) 1/2+1/6+1/12+1/20+....+1/56
=1/1x2+1/2x3+1/3x4+1/4x5+.....1/7x8
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.......-1/7+1/7-1/8
=1/1-1/8
=7/8
c) mình chịu
Trả lời
1)3425:15=228,333...
547:12=45,58333...
2)
a)48:12+5*37-23
=4+162
=166
b)
84:{45:[(135+45):3-7.8]+3}
=84:{45:[180:3-7.8]+3}
=84:{45:4+3}
=84:14,25
=5,8947...
1)
3425 : 15 = 228 (dư 5)
547 : 12 = 45 ( dư 7)
2) Tính
a) 48 : 12 + 5 x 37 - 23
= 4 + 185 - 23
= 189 - 23
= 166
b) 84 : {45:[(135 + 45) : 3 - 7 x 8] + 3}
= 84 : {45 : [180 : 3 - 7 x 8] + 3}
= 84 : {45 : [60 - 56] +3}
= 84 : {45 : 4 + 3}
= 84 : {11,25 + 3}
= 84 : 14,25
= \(\frac{112}{19}\)
\(\frac{4}{3}+\frac{x}{3}\text{ × }7=6\)
\(\frac{x}{3}\text{ × }7=6-\frac{4}{3}\)
\(\frac{x}{3}=\frac{14}{3}:7\)
\(\frac{x}{3}=\frac{2}{3}\)
\(\Leftrightarrow x=2\)
Các phần còn lại bạn làm tương tự nha
\(\frac{1}{3}+\frac{3}{7}+\frac{5}{3}+\frac{8}{14}\)
\(=\left(\frac{1}{3}+\frac{5}{3}\right)+\left(\frac{3}{7}+\frac{8}{14}\right)\)
\(=\frac{6}{3}+\left(\frac{6}{14}+\frac{8}{14}\right)\)
\(=2+\frac{14}{14}\)
\(=2+1\)
\(=3\)
\(\frac{5}{6}+\frac{4}{15}+\frac{6}{18}+\frac{3}{45}\)
\(=\left(\frac{5}{6}+\frac{6}{18}\right)+\left(\frac{4}{15}+\frac{3}{45}\right)\)
\(=\left(\frac{5}{6}+\frac{2}{6}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)
\(=\frac{7}{6}+\frac{5}{15}\)
\(=\frac{7}{6}+\frac{1}{3}\)
\(=\frac{7}{6}+\frac{2}{6}\)
\(=\frac{9}{6}\)
\(=\frac{3}{2}\)
~ Ủng hộ nhé
\(9\times17+83\times9\)
\(=\left(83+17\right)\times9\)
\(=100\times9\)
\(=900\)
\(4\frac{1}{7}+7+8\frac{6}{7}\)
\(=\left(4\frac{1}{7}+8\frac{6}{7}\right)+7\)
\(=\left(8+4\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+7\)
\(=12+\frac{7}{7}+7\)
\(=12+1+7\)
\(=20\)
~ Ủng hộ nhé
\(\text{Đặt A }=\frac{1}{15}+\frac{2}{45}+\frac{3}{135}+\frac{4}{345}+\frac{5}{759}\)
\(\Rightarrow A=\frac{1}{3.5}+\frac{2}{5.9}+\frac{3}{9.15}+\frac{4}{15.23}+\frac{5}{23.33}\)
\(\Rightarrow2A=2\left(\frac{1}{3.5}+\frac{2}{5.9}+\frac{3}{9.15}+\frac{4}{15.23}+\frac{5}{23.33}\right)\)
\(\Leftrightarrow2A=\frac{2}{3.5}+\frac{4}{5.9}+\frac{6}{9.15}+\frac{8}{15.23}+\frac{10}{23.33}\)
\(\Leftrightarrow2A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{15}+\frac{1}{15}-\frac{1}{23}+\frac{1}{23}-\frac{1}{33}\)(Tại sao ra vậy cứ ib giải thích cho)
\(\Rightarrow2A=\frac{1}{3}-\frac{1}{33}\)
\(\Leftrightarrow2A=\frac{10}{33}\)
\(\Rightarrow A=\frac{10}{33}:2=\frac{5}{33}\)
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