bạn nào giải  thích rõ ràng  ba k sẽ thụôc về bạn

a) -4/9 * 7/15 + 4/-9 * 8/15

= -4/9 * 7/15 + -4/9 * 8/15 ( 4/-9 = -4/9 )

= -4/9 * ( 7/15 + 8/15 )

= -4/9 * 1 = -4/9

b) 5/-4 * 16/25 + (-5/4) * 9/25

= -5/4 * 16/25 + -5/4 * 9/25 ( 5/-4 = -5/4 )

= -5/4 * ( 16/25 + 9/25 )
= -5/4 * 1 = -5/4

c) 4 11/23 chắc chắn là hỗn số rồi

Câu c) để sau

\(\dfrac{-5}{9}+\dfrac{8}{15}+\dfrac{-2}{11}+\dfrac{4}{-9}+\dfrac{7}{15}\)

=\(\left(\dfrac{-5}{9}+\dfrac{-4}{9}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)-\dfrac{2}{11}\)

=\(-1+1-\dfrac{2}{11}=\dfrac{-2}{11}\)

\(=\left(\dfrac{-5}{9}+\dfrac{-4}{9}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)+\dfrac{-2}{11}\\ =-1+1+\dfrac{-2}{11}\\ =0+\dfrac{-2}{11}=\dfrac{-2}{11}\)

B=-5/9+8/15+-2/11+4/9+7/15

=>B=(-5/9+4/-9)+(8/15+7/15)-2/11

=>B=(-5/9+-4/9)+1-2/11

=>B=-1+1-2/11

=>B=-2/11

Vậy B=-2/11

Ta có :

B=-5/9+8/15+-2/11+4/9+7/15

=>B=(-5/9+4/-9)+(8/15+7/15)-2/11

=>B=(-5/9+-4/9)+1-2/11

=>B=-1+1-2/11

=>B=-2/11

Vậy B=-2/11

\(\dfrac{-4}{9}.\dfrac{7}{15}+\dfrac{4}{-9}.\dfrac{8}{15}\)

\(=\dfrac{-4}{9}.\dfrac{7}{15}+\dfrac{-4}{9}.\dfrac{8}{15}\)

\(=\dfrac{-4}{9}.\left(\dfrac{7}{15}+\dfrac{8}{15}\right)\)

\(=\dfrac{-4}{9}.1\)

\(=\dfrac{-4}{9}\)

Tách hai dấu ngoặc thành hai vế A và B

Ta có : 

A=5.4¹⁵.9⁹-4.3²⁰.8⁹=5.2³⁰.3¹⁸-2².2²⁷.3²⁰

=2²⁹.3¹⁸(2.5-3²)=2²⁹.3¹⁸

B=5.2⁹.6¹⁹-7.2²⁹.27⁶=5.2⁹.2¹⁹.3¹⁹-7.2²⁹.3¹⁸

=2²⁸.3¹⁸(5.3-7.2)=2²⁸.3¹⁸

=>A:B=2²⁹.3¹⁸:2²⁸:3¹⁸=2

a, \(\dfrac{3}{15}-x=-\dfrac{1}{7}\Leftrightarrow\dfrac{21-105x}{105}=\dfrac{-15}{105}\Rightarrow-105x=-36\)

\(\Leftrightarrow x=\dfrac{36}{105}=\dfrac{12}{35}\)

b, \(\left(4,5+\dfrac{3}{4}x\right):\dfrac{8}{3}=\dfrac{9}{3}\Leftrightarrow\dfrac{45}{10}+\dfrac{3x}{4}=\dfrac{72}{9}=8\)

\(\Leftrightarrow\dfrac{36}{4}+\dfrac{3x}{4}=\dfrac{32}{4}\Rightarrow3x=-4\Leftrightarrow x=-\dfrac{4}{3}\)

c, mình ko hiểu đề lắm 

1: \(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}\right)+\dfrac{16}{15}\left(\dfrac{4}{7}-\dfrac{5}{9}\right)\)

\(=\dfrac{16}{15}\left(-\dfrac{4}{9}+\dfrac{3}{7}+\dfrac{4}{7}-\dfrac{5}{9}\right)=0\)

2: \(=\dfrac{29}{9}\left(15+\dfrac{4}{7}-8-\dfrac{1}{7}+\dfrac{15}{7}-\dfrac{1}{7}\right)\)

\(=\dfrac{20}{9}\cdot\left(7\cdot\dfrac{18}{7}\right)=\dfrac{20}{9}\cdot18=40\)