=  225.55 +  225.55

=  451.1 

a)\(65.3,47+3,47.65\)
\(=65.\left(3,47+3,47\right)\)
\(=65.6,94\)
\(=451,1\)

=8,95*90+89,5

=89,5(9+1)

=895

=34,5x5,789+4,211x34,5
=34,5x(5,789+4,211)
=34,5x10
=345

a: \(20,11\cdot7,5+20,11+20,11+20,11\cdot0,5\)

\(=20,11\left(7,5+1+1+0,5\right)\)

\(=20,11\cdot10=201,1\)

b: \(2,5\cdot12,85\cdot4\)

\(=12,85\cdot\left(2,5\cdot4\right)\)

\(=12,85\cdot10=128,5\)

a: 

b: 

Ta tách 9 x 24 ra 27 x 8

(77 + 8 + 15) x 27

= 100 x 27

= 2700

số số hạng là :`(26 - 2) : 2 + 1 = 13(số hạng)`

`13 : 2 = 12 dư 1 `

`=>A = (2 - 4) + (6 - 8) + (10 - 12) + ... + (22 - 24) + 26`

`=>A = (-2) + (-2) + (-2) + ... + (-2) + 26`

`=>A = (-2) xx 6 + 26`

`=> A = -12 + 26`

`=> A = 14`

A=[(26-2):4+1].(2-4)

A=[24:4+1].(-2)

A=7.(-2)

A=-14

Lời giải:

$A=(99-97)+(95-93)+(91-89)+...+(7-5)+(8-1)$

$=\underbrace{2+2+2+...+2}_{24}+7$

$=2\times 24+7$

$=55$

Ta có: 99–97 +95–93+...+7–5+3−1

=(99−97)+(95−93)+...+(7−5)+(3−1)

=2+2+...+2+2 (có 25 số 2)

=2.25

=50

=(-0,2)+0,5+0,5+0,5+0,5+0,5+0,5

=2,8

`A=1/[1xx2xx3]+1/[2xx3xx4]+1/[3xx4xx5]+....+1/[98xx99xx100]`

`A=1/2xx(2/[1xx2xx3]+2/[2xx3xx4]+2/[3xx4xx5]+....+2/[98xx99xx100])`

`A=1/2xx(1/[1xx2]-1/[2xx3]+1/[2xx3]-1/[3xx4]+1/[3xx4]-1/[4xx5]+....+1/[98xx99]-1/[99xx100])`

`A=1/2xx(1/[1xx2]-1/[99xx100])`

`A=1/2xx(1/2-1/9900)`

`A=1/2xx(4950/9900-1/9900)`

`A=1/2xx4949/9900`

`A=4949/19800`

\(A=\dfrac{3-1}{1.2.3}+\dfrac{4-2}{2.3.4}+\dfrac{5-3}{3.4.5}+...+\dfrac{100-98}{98.99.100}\)

\(A=\left(\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{98.99}-\dfrac{1}{99.100}\right):2\)

\(A=\left(\dfrac{1}{2}-\dfrac{1}{6}+\dfrac{1}{12}-\dfrac{1}{20}+...+\dfrac{1}{9702}-\dfrac{1}{990}\right):2\)

\(A=\left(\dfrac{1}{2}-\dfrac{1}{990}\right):2\)

\(A=\dfrac{4949}{9900}:2\)

\(A=\dfrac{4949}{19800}\)