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c) 93.32+14.16=93.2.16+14.16=16.(186+14)=16.200=3200
e)-8.40+2.108+24=24(9+1)-320=240-320=-80
b)86.15+150.1,4=86.15+15.14=15(86+14)=15.100=1500
d)98,6.199-990.9,86=98,6.199-99.98,6=98,6(199-99)=98,6.100=9860
f)993.98+21.331-50.99,3=993.(98+7-5)=993.100=99300
b) Ta có: \(86\cdot15+150\cdot1.4\)
\(=86\cdot15+14\cdot15\)
\(=15\left(86+14\right)\)
=1500
c) Ta có: \(93\cdot32+14\cdot16\)
\(=186\cdot16+14\cdot16\)
\(=16\left(186+14\right)\)
\(=16\cdot200=3200\)
a) \(52^2\)
\(=\left(50+2\right)^2\)
\(=50^2+2\cdot2\cdot50+2^2\)
\(=2500+200+4\)
\(=2704\)
b) \(98^2\)
\(=\left(100-2\right)^2\)
\(=100^2-2\cdot100\cdot2+2^2\)
\(=10000-400+4\)
\(=9604\)
`a, 52^2 = (50+2)^2 = 2500 + 200 + 4 = 2704`
`b, 98^2 = (100-2)^2 = 100^2 - 2 . 100 . 2 + 4 = 10000 - 400 + 4`
`= 9604`
a) \(82\cdot78\)
\(=\left(80+2\right)\cdot\left(80-2\right)\)
\(=80^2-2^2\)
\(=6400-4\)
\(=6396\)
b) \(87\cdot93\)
\(=\left(90-3\right)\left(90+3\right)\)
\(=90^2-3^2\)
\(=8100-9\)
\(=8091\)
c) \(125^2-25^2\)
\(=\left(125-25\right)\left(125+25\right)\)
\(=100\cdot150\)
\(=15000\)
`a, 38 . 42 = (40-2)(40+2) = 1600 - 4 = 1596`.`
`b, 102^2 = (100+2)^2 = 10000 + 400 + 4 = 10404`
`c, 198^2 = (200-2)^2 = 40000 - 800 + 4 = 39204`
`d, 75^2 - 25^2 = (75+25)(75-25) = 100. 50 = 5000`
3A:
a: \(75\cdot20.9+5^2\cdot20.9\)
\(=20.9\cdot100\)
=2090
b: \(86\cdot15+150\cdot1.4\)
\(=86\cdot15+15\cdot14\)
\(=15\cdot100=1500\)
c: \(93\cdot32+14\cdot16\)
\(=93\cdot32+32\cdot7\)
=3200
\(a.75^2-50.75+25^2\\ =75^2-2.25.75+25^2\\ =\left(75-25\right)^2=50^2=2500\)
\(b.103.97\\ =\left(100+3\right)\left(100-3\right)\\ =100^2-3^2\\ =9991\)
\(a,75^2-50.75+25^2\\ =75^2-2.75.25+25^2\\ =\left(75+25\right)^2=100^2=10000\\ b,103.97\\ =\left(100+3\right).\left(100-3\right)\\ =100^2-3^2=10000-9=9991\)
a. Ta có: \(17^2-14.17+49=17^2-2.7.17+7^2=\left(17-7\right)^2=10^2=100\)
b. \(2021^2-2020^2=\left(2021-2020\right)\left(2021+2020\right)=4041\)
a) Kết quả -80. b) Kết quả 993000.