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S=1/1.3.5 +1/3.5.7+...................+1/19.21.23
---> 4S=4/1.3.5 + 4/ 3.5.7 +.........................+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +...................................+(1/... -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483 =160/483
----> S = 160/483 : 4 = 160 / 1932
(em tự rút gọn nhé! )S=1/1.3.5 +1/3.5.7+...................+1/19.21.23
---> 4S=4/1.3.5 + 4/ 3.5.7 +.........................+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +...................................+(1/... -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483 =160/483
----> S = 160/483 : 4 = 160 / 1932
(em tự rút gọn nhé! )
M=1/1.3.5 +1/3.5.7+.....+1/19.21.23
4M=4/1.3.5 + 4/ 3.5.7 +...+4/19.21.23
= (1/1.3 -1/3.5 ) + ( 1/3.5 -1/3.7) +....+(1/19.21 -1/21.23 )
= 1/1.3 -1/21.23
= 1/3 -1/483
=160/483
⇒ S = 160/483 : 4
= 160 / 1932
=40/438
\(a.\)
\(-\left(-315\right)+\left(-115\right)-105+25\)
\(315-115-105+25\)
\(=215\)
\(b.\)
\(888-\left(-333\right)-222+111\)
\(=888+333-222+111\)
\(=1110\)
\(c.\)
\(-97-15+44-35-12+98\)
\(=-17\)
\(A=\frac{1}{15}+\frac{1}{105}+...+\frac{1}{2145}\)
\(=\frac{1}{1.3.5}+\frac{1}{3.5.7}+...+\frac{1}{11.13.15}\)
\(=\frac{1}{4}\left[\frac{4}{1.3.5}+\frac{4}{3.5.7}+...+\frac{4}{11.13.15}\right]\)
\(=\frac{1}{4}.\left[\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{11.13}-\frac{1}{13.15}\right]\)
\(=\frac{1}{4}.\left[\frac{1}{1.3}-\frac{1}{13.15}\right]=\frac{1}{4}.\left[\frac{1}{3}-\frac{1}{195}\right]=\frac{16}{195}\)
\(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\Rightarrow\frac{3}{x}=\frac{5-2y}{6}\)
\(\Rightarrow x\left(5-2y\right)=18\)
Từ đó tìm được x,y
[ ( 9 - 18 ) + ( -17 ) ] + ( -15 )
= [ ( -9 ) + ( -17 ) ] + ( -15 )
= ( -26 ) + ( -15 )
= -41
666 - ( -442 ) - 100 - 88
= 666 + 442 - 100 - 88
= 1108 - 100 - 88
= 1008 - 88
= 920
- ( -315 ) + ( -115 ) - 105 + 25
= 315 + ( -115 ) - 105 + 25
= 200 - 105 + 25
= 95 + 25
= 120
888 - ( -333 ) - 222 + 70
= 888 + 333 - 222 + 70
= 1221 - 222 + 70
= 999 + 70
= 1069
Tính tổng : 1/15+1/105+...+1/2145