`a) 465 + [ 58 + ( -465 ) + ( -38 ) ]`

`= 465 + 58 - 465 -38`

`= (465-465) + (58-38)`

`=0+ 20`

`=20`

`b) ( 35 - 17 ) + ( 17 + 20 - 35 )`

`= 35 -17 +17 +20-35`

`= (35-35) + (-17+17)+20`

`= 0 + 0 +20`

`=20`

$a)465+[58+(-465)+(-38)]$

=465+58−465−38$=465+58-465-38$

=(465−465)+(58−38)$=(465-465)+(58-38)$

=0+20$=0+20$

=20$=20$

�)(35−17)+(17+20−35)$b)(35-17)+(17+20-35)$

=35−17+17+20−35$=35-17+17+20-35$

=(35−35)+(−17+17)+20$=(35-35)+(-17+17)+20$

=0+0+20$=0+0+20$

=20$=20$

(35+17)+(17+20-35)

=35+17+17+20-35

=(35-35)+(17+17+20)

=0+54

=54

tk m nha!

thanks nha

1;  (-8537 ) + ( 1975 + 8537)

=   - 8537   + 1975 + 8537

=  (-8537    +  8537) + 1975

= 0 + 1975

= 1975

2; ( 35 - 17 ) - ( -17 + 20 + 35)

= 35 - 17 + 17 - 20 - 35

= ( 35 - 35) + ( -17 + 17) - 20

= 0 + 0 - 20

= - 20 

(35-17)+(17+20-35)

=35-17+17+20-35

=(35-35)+(-17+17)+20

=0+0+20

=20

\(\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}+\frac{-8}{13}\)

\(=\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{-17}{35}+\frac{-8}{13}\)

\(=\left(\frac{3}{17}+\frac{14}{17}\right)+\left(\frac{-5}{13}+\frac{-8}{13}\right)+\left(\frac{-18}{35}+\frac{-17}{35}\right)\)

\(=\frac{17}{17}+\frac{-13}{13}+\frac{-35}{35}\)

\(=1+\left(-1\right)+\left(-1\right)\)

\(=-1\)

\(\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{17}{-35}+\frac{-8}{13}\)

= \(\frac{3}{17}+\frac{-5}{13}+\frac{-18}{35}+\frac{14}{17}+\frac{-17}{35}+\frac{-8}{13}\)

= \(\left(\frac{3}{17}+\frac{14}{17}\right)+\left(\frac{-5}{13}+\frac{-8}{13}\right)+\frac{-18}{35}\)

= 1+(-1)+\(\frac{-18}{35}\)

= 0+\(\frac{-18}{35}\)

= \(\frac{-18}{35}\)

Trình bày chi tiết ra được không?

\(\frac{32}{17}:\frac{9}{2}+\frac{35}{17}:\frac{9}{3}+\frac{35}{17}:\frac{9}{4}\)

\(=\frac{32}{17}:\left(\frac{9}{2}+\frac{9}{3}+\frac{9}{4}\right)\)

\(=\frac{32}{17}:\frac{39}{4}\)

\(=\frac{128}{663}\)