\(B=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)

\(=10101\cdot\dfrac{1}{31746}=\dfrac{7}{22}\)

10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

= 10101 . \(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

= 10101 . \(\frac{7}{222222}\)

= \(\frac{7}{22}\)

Lời giải:

Ta có:

\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)

\(=10101.\left(\frac{10+5-8}{222222}\right)\)

\(=10101.\frac{7}{222222}\)

\(=\frac{7.10101}{22.10101}=\frac{7}{22}\)

Chúc bạn học tốt!Tick cho mình nhé!

b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)

\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)

\(=5\)

c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)

A = 1.2.3+2³.1.2.3+3³.1.2.3+4³.1.2.3 /3.4.5+2³.3.4.5+3³.3.4.5+4³.3.4.5

   =1.2.3 (1+2³+3³+4³)/3.4.5 (1+2³+3³+4³)

   =1.2.3/3.4.5

   =1/10

B=10101 ( 15/333333 + 2/333333 +57 / 333333 )

B=10101 . 74 /333333

  =74/33

bai....................kho......................wa.....................troi.........................thi.................lanh...............lai....................mua...................tich....................ung.....................ho..................minh....................nha.......................huhu

\(P=-\frac{7}{4}.\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)\)

\(P=-\frac{7}{4}.\left(\frac{33}{12}+\frac{33.101}{20.101}+\frac{33x10101}{30x10101}+\frac{33x1010101}{42x1010101}\right)\)

\(P=-\frac{7}{4}.\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)

\(P=-\frac{7}{4}.\left(\frac{11}{4}+\frac{33}{20}+\frac{11}{10}+\frac{11}{14}\right)\)

\(P=-\frac{77}{8}.\left(\frac{1}{6}+\frac{3}{10}+\frac{1}{15}+\frac{1}{21}\right)=-\frac{77}{8}.\frac{35+63+14+10}{210}=-\frac{11x122}{8x30}\)

\(P=-\frac{671}{120}\)

P = -7/4 x (33/12 + 3333/2020 + 333333/303030 + 33333333/42424242)
   = -7/4 x (33/12 + 33/20 + 33/30 + 33/42)
   = -7/4 x [33 x (1/12 + 1/20 + 1/30 + 1/42)]
   = -7/4 x [33 x (35/420 + 21/420 + 14/420 + 10/420)]
   = -7/4 x (33 x 80/420)
   = -7/4 x  33 x 4/21
   = -7/4 x 4/21 x 33 (= -7x4 / 4x21   x33)
   = -7/21 x 33 (= -7x33 / 21 = -1x7x3x11 / 3x7)
   = -11/1
   = -11
Đáp số P = -11

Các số gạch đi là do rút gọn phân số nhé!!!