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a: \(\dfrac{5}{7}=\dfrac{5\cdot11}{7\cdot11}=\dfrac{55}{77}\)
\(\dfrac{9}{11}=\dfrac{9\cdot7}{11\cdot7}=\dfrac{63}{77}\)
b: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot9}{7\cdot9}=\dfrac{54}{63}\)
\(-\dfrac{12}{54}=\dfrac{-2}{9}=\dfrac{-2\cdot7}{9\cdot7}=-\dfrac{14}{63}\)
c: \(\dfrac{-11}{30}=\dfrac{-11\cdot4}{30\cdot4}=\dfrac{-44}{120}\)
\(\dfrac{-17}{-40}=\dfrac{17}{40}=\dfrac{17\cdot3}{40\cdot3}=\dfrac{51}{120}\)
d: \(\dfrac{36}{42}=\dfrac{6}{7}=\dfrac{6\cdot3}{7\cdot3}=\dfrac{18}{21}\)
\(\dfrac{-12}{36}=\dfrac{-1}{3}=\dfrac{-1\cdot7}{3\cdot7}=\dfrac{-7}{21}\)
\(\dfrac{14}{21}=\dfrac{7\cdot2}{7\cdot3}=\dfrac{2}{3}\)
\(\dfrac{-36}{48}=\dfrac{-12\cdot3}{12\cdot4}=-\dfrac{3}{4}\)
\(\dfrac{28}{-52}=\dfrac{7\cdot4}{-4\cdot13}=-\dfrac{7}{13}\)
\(\dfrac{-54}{-90}=\dfrac{-18\cdot3}{-18\cdot5}=\dfrac{3}{5}\)
\(\dfrac{14}{21}\) =\(\dfrac{2}{3}\)
\(\dfrac{-36}{48}\) =\(\dfrac{3}{4}\)
\(\dfrac{28}{-52}\)=\(\dfrac{7}{-13}\)
\(\dfrac{-54}{-90}\) =\(\dfrac{6}{9}=\dfrac{2}{3}\)
a, Gọi d là UCLN (n+7; n+8) (d ∈ Z)
Ta có n+7 ⋮ d ; n+8 ⋮ d ➞ (n+7) - (n+8) ⋮ d ⇒ -1 ⋮ d
⇒ d ∈ Ư (-1) = (+-1)
⇒ \(\dfrac{\left(n+7\right)}{n+8}\) là phân số tối giản
từ đo bạn tự làm được không?
\(a,MSC:180\\ \dfrac{17}{12}=\dfrac{17.15}{12.15}=\dfrac{255}{180};\dfrac{31}{18}=\dfrac{31.10}{18.10}=\dfrac{310}{180};\dfrac{8}{15}=\dfrac{8.12}{15.12}=\dfrac{96}{180}\\ b,MSC:75\\ \dfrac{7}{15}=\dfrac{7.5}{15.5}=\dfrac{35}{75};\dfrac{8}{25}=\dfrac{8.3}{25.3}=\dfrac{24}{75};\dfrac{11}{75}=\dfrac{11}{75}\)
Ta có:
\(\dfrac{4}{12}=\dfrac{1}{3}\)
\(\dfrac{5}{20}=\dfrac{1}{4}\)
\(\dfrac{21}{35}=\dfrac{3}{5}\)
\(\dfrac{17}{34}=\dfrac{1}{2}\)
Vậy \(\dfrac{17}{34}=\dfrac{1}{2}\)
B
B