biết có mấy câu à

2+2+2=6

3.3- 3 = 6

6.6:6=6

còn mấy câu kia thì ........................tịt,mk ms lớp 6 à

\(\left(1+1+1\right)!=6.\)

\(2+2+2=6\)

\(3.3-3=6\)

\(\sqrt{4}+\sqrt{4}.\sqrt{4}=6\)

\(5+5\div5=6\)

\(6.6\div6=6\)

\(7-7\div7=6\)

\(\sqrt{8+8\div8}!=6\)

\(\sqrt{9}.\sqrt{9}-\sqrt{9}=6\)

\(\sqrt{10-10\div10}!\)

2+2+2=6

3x3-3=6

6+6-6=6

(1+1+1)!=3 ( ko thêm số nhé)

căn 4 + căn4 + căn4 = 6( tính mà xem)

5+(5/5)=6

7-(7/7)=6

Căn(8/8)+8 !=6

(9-9)+căn9 !=6

Căn10-(10/10) !=6

đúng tk mik nha

(1+1+1)!=6

2+2+2=6

3.3-3=6

\(\sqrt{4}+\sqrt{4}+\sqrt{4}=6\)6

5+5:5 =6

6+6-6=6

7-7:7=6

\(\left(\sqrt{8+8:8}\right)!=6\)

\(\left(\sqrt{9-9+9}\right)!=6\)

\(\left(\sqrt{10+10:10}\right)!\)=6

2+2+2=6

3.3-3=6

5:5+5=6

6+6-6=6

1/ \(7-2\sqrt{6}=\left(\sqrt{6}\right)^2-2\sqrt{6}+1\)

\(=\left(\sqrt{6}-1\right)^2\)

2/ \(10+2\sqrt{21}=\left(\sqrt{7}\right)^2+2.\sqrt{7}.\sqrt{3}+\left(\sqrt{3}\right)^2\)

\(=\left(\sqrt{7}+\sqrt{3}\right)^2\)

4/ \(10+4\sqrt{6}=2^2+2.2.\sqrt{6}+\left(\sqrt{6}\right)^2\)

\(=\left(2+\sqrt{6}\right)^2\)

5/ \(11-2\sqrt{30}=\left(\sqrt{6}\right)^2-2.\sqrt{6}.\sqrt{5}+\left(\sqrt{5}\right)^2\)

= \(\left(\sqrt{6}-\sqrt{5}\right)^2\)

8/ \(11+4\sqrt{7}=2^2+2.2.\sqrt{7}+\left(\sqrt{7}\right)^2\)

= \(\left(2+\sqrt{7}\right)^2\)

10/ \(12+6\sqrt{3}=3^2+2.3.\sqrt{3}+\left(\sqrt{3}\right)^2\)

= \(\left(3+\sqrt{3}\right)^2\)

(1+1+1)! = 3! = 6

2+2+2=6

3x3-3=6

\(\sqrt{4}+\sqrt{4}+\sqrt{4}=6\)

5:5+5=6

6+(6-6)=6

7-7:7=6

\(8-\sqrt{\sqrt{8+8}}=6\)

\(\sqrt{9}.\sqrt{9}-\sqrt{9}=6\)