125=5³=

-125=(-5)³

27=3³

-27=(-3)³

125 =5³ - 125=(-5)³ ; 27 =3³; - 27 =(-3)³

\(125=5^3\)

\(-125=\left(-5\right)^3\)

\(27=3^3\)

\(-27=\left(-3\right)^3\)

 ^...^ ^_^

Bài 11: Viết các số sau dưới dạng lũy thừa với số mũ khác 1:

125 = 5³

(-125) = (-5)³

27 = 3³

(-27) = (-3)³

125 = 125^2-1 ; - 125 = - 125^1009-1008 ; 27 = 27^{10000000000-9999999999} ; - 27 = - 27^{\(\infty+1-\infty\)}             :)

1=1^2 ;125=5^3 ;-125=-5^3; 27=27^1; -27= -27^1

2: 5^2 25^1 

\(\dfrac{9}{25}=\left(\dfrac{3}{5}\right)^2\)

\(\dfrac{8}{27}=\left(\dfrac{2}{3}\right)^3\)

\(\dfrac{-125}{64}=\left(-\dfrac{5}{4}\right)^3\)

\(0=0^2\)

\(-27=\left(-3\right)^3\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(125=5^3\)
\(-125=\left(-5^3\right)\)

\(27=3^3\)

\(-27=\left(-3^3\right)\)

125 = 5^3

-125 = (-5^3)

27= 3^3

-27=( -3^3)

0,25 = (0,5)²

\(\dfrac{1}{49}\) = (\(\dfrac{1}{7}\))²

- \(\dfrac{27}{125}\) = (- \(\dfrac{3}{5}\))³

 \(\dfrac{81}{16}\) = ( \(\dfrac{9}{4}\))²

\(\dfrac{169}{196}\) = (\(\dfrac{13}{14}\))²

\(\begin{array}{l}0,49 = {\left( {0,7} \right)^2};\\\,\frac{1}{{32}} =\frac{1^5}{2^5}={\left( {\frac{1}{2}} \right)^5};\\\,\frac{{ - 8}}{{125}} =\frac{(-2)^3}{5^3}= {\left( {\frac{{ - 2}}{5}} \right)^3};\end{array}\)

\(\frac{{16}}{{81}} =\frac{4^2}{9^2}= {\left( {\frac{4}{9}} \right)^2} (hoặc \,\frac{{16}}{{81}} =\frac{2^4}{3^4}= {\left( {\frac{2}{3}} \right)^4});\\\,\frac{{121}}{{169}} =\frac{11^2}{13^2}= {\left( {\frac{{11}}{{13}}} \right)^2}\)