1+1=3

\(\hept{\begin{cases}\\\\\end{cases}1345}\)

=10¹⁰-1/9   -   2.(10⁵-1)/9 

=10¹⁰-1-2.10⁵+2/9

=(10⁵-1)²/9

=(10⁵-1/3)² 

cau b ban co nham de ko

Chịu

`10.1000.100000`

`=10^{1}.10^{3}.10^{5}`

`=10^{1+3+5}`

`=10^{9}`

A = 1111111111 – 22222=1111x10001-2x1111=1111(10001-2)=1111x9999=1111.3.3333=3333x3333=3333^2

=>..............

Ta có

\(1111111111=\frac{9999999999}{9}=\frac{9999999999+1-1}{9}=\frac{10^{10}-1}{9}.\)

\(22222=2.11111=\frac{2.99999}{9}=\frac{2\left(99999+1-1\right)}{9}=\frac{2\left(10^5-1\right)}{9}\)

\(\Rightarrow A=\frac{10^{10}}{9}-\frac{1}{9}-2.\frac{10^5}{9}+\frac{2}{9}=\)

\(=\left(\frac{10^5}{3}\right)^2-2.\frac{10^5}{3}.\frac{1}{3}+\left(\frac{1}{3}\right)^2=\left(\frac{10^5}{3}-\frac{1}{3}\right)^2\)

a: 6*6*6*6*6=6^5

b: 25*25*25*5=5^2*5^2*5^2*5=5^7

c: 8*2*2*16*4

=2^3*2^2*2^4*2^2

=2^11

d: \(3\cdot3\cdot3\cdot15\cdot5\cdot5\cdot5=15\cdot15\cdot15\cdot15=15^4\)

42,11,22

\(2013=2.1000+10+3=2.10^3+1.10^1+3.10^0\)

\(20112013=2.10000000+100000+10000+2.1000+10+3\)

\(=2.10^7+10^5+10^4+2.10^3+10^1+3.10^0\)

2013 = 2 x 1000 + 10 + 3 = 2 x 10^3 + 1 . 10^1 + 3 . 10^0

20112013 = 2 x 10000000 + 100000 + 2 x 1000 + 10 + 3 =  2 x 10^7 + 10^5 + 10^4 + 2 x 10^3 + 10^1 + 3 x 10^0

ok nhé với lại 10^2 là 10 mũ 2 nhé =>