\(\left(2x-4y\right)^2+2\left(2x-4y\right)+1=\left(2x-4y+1\right)^2\)

(2x-4y)²+2(2x-4y)+1

=(2x-4y)²+2(2x-4y)+1²

=(2x-4y+1)²

x^2 + 4y^2 -6x + 4y +10

=x²-6x+9+4y²+4y+1

=(x-3)²+(2y+1)²

x^2-4y^2-6x+4y+10

= x^2- 2.x.3 + 9 + 4y^2-2.2y+1

= ( x - 3)^2+ (2y-1) ^2

a/ \(=\left(9x^2+30x+25\right)+\left(x^2+10x+25\right)=\)

\(=\left(3x+5\right)^2+\left(x+5\right)^2\)

b/ \(=\left(16x^2+8x+1\right)+\left(y^2-4y+4\right)=\left(4x+1\right)^2+\left(y-2\right)^2\)

c/ 

`x^2-2x+4y^2+4y+2`

`=x^2-2x+1+4y^2+4y+1`

`=(x-1)^2+(2y+1)^2`

Ta có: \(x^2-2x+2+4y^2+4y\)

\(=x^2-2x+1+4y^2+4y+1\)

\(=\left(x-1\right)^2+\left(2y+1\right)^2\)

a, \(25x^2+5xy+\frac{1}{4}y^2=\left(5x\right)^2+2.5x.\frac{1}{2}y+\left(\frac{1}{2}y\right)^2\)

\(=\left(5x+\frac{1}{2}y\right)^2\)

b, \(9x^2+12x+4=\left(3x\right)^2+2.3x.2+2^2=\left(3x+2\right)^2\)

c, \(x^2-6x+5-y^2-4y=\left(x^2-6x+9\right)-\left(y^2+4y+4\right)\)

\(=\left(x-3\right)^2-\left(y+2\right)^2=\left(x-y-5\right)\left(x+y-1\right)\)

d, \(\left(2x-y\right)^2+4\left(x+y\right)^2-4\left(2x-y\right)\left(x+y\right)\)

\(=\left(2x-y\right)^2-2\left(2x-y\right)\left(2x+2y\right)+\left(2x+2y\right)^2\)

\(=\left(2x-y+2x+2y\right)^2=\left(4x+y\right)^2\)

Có cái cc

a) t² - 8t + x² - 4x + 20 = ( t² - 8t + 16 ) + ( x² - 4x + 4 ) = ( t - 4 )² + ( x - 2 )²

b) 49t² + y² - 10y + 14t + 26 = ( 49t² + 14t + 1 ) + ( y² - 10y + 25 ) = ( 7t + 1 )² + ( y - 5 )²

c) 2x² + 4y² - 2x + 4xy + 1 = ( x² - 2x + 1 ) + ( x² + 4xy + 4y² ) = ( x - 1 )² + ( x + 2y )² ( thay 2 thành 1 vì 2 khó làm lắm:v )

Câu 1:

a, (x-1).(x²-x+1)

b, (2a+b).(2a-b)

Câu 2:

a,(2x-1).(x²-5x+3)

b,(-x²+4x-1).(-x+4)

c,(-2x-3).(x+4)+(-x+1)

d,(-3).(x+4).(x-7)+2.(x-5).(x+1)

Câu 3:

a,5x²-(2x+1).(x-2)-x.(3x+3)+7

b,(5x-2).(x+1)-(x-3).5x+1-17.(x-2)

Giup mình với 

Mình gửi kiểu kia ko được

a) x² + 4y + 4y² + 26 - 10x = ( x² - 10x + 25 ) + ( 4y² + 4y + 1 ) = ( x - 5 )² + ( 2y + 1 )²

b) 4y² + 34 - 10x + 12y + x² = ( x² - 10x + 25 ) + ( 4y² + 12y + 9 ) = ( x - 5 )² + ( 2y + 3 )²

c) -10x + y² - 8y + x² + 41 = ( x² - 10x + 25 ) + ( y² - 8y + 16 ) = ( x - 5 )² + ( y - 4 )²

d) x² + 9y² - 12y + 29 - 10x = ( x² - 10x + 25 ) + ( 9y² - 12y + 4 ) = ( x - 5 )² + ( 3y - 2 )²

a) \(x^2+4y+4y^2+26-10x\)

\(=\left(x^2-10x+25\right)+\left(4y^2+4y+1\right)\)

\(=\left(x-5\right)^2+\left(2y+1\right)^2\)

b) \(4y^2+34-10x+12y+x^2\) đề ntn à?

\(=\left(4y^2+12y+9\right)+\left(x^2-10x+25\right)\)

\(=\left(2y-3\right)^2+\left(x-5\right)^2\)

c) \(-10x+y^2-8y+x^2+41\)

\(=\left(x^2-10x+25\right)+\left(y^2-8y+16\right)\)

\(=\left(x-5\right)^2+\left(y-4\right)^2\)

d) \(x^2+9y^2-12y+29-10x\)

\(=\left(x^2-10x+25\right)+\left(9y^2-12y+4\right)\)

\(=\left(x-5\right)^2+\left(3y-2\right)^2\)

a, Đề sai bạn ơi phải là cộng 16 chứ không phải cộng 4

b,B= (x-2y+1)^2

thế còn c với d

a) Ta có: \(\left(x^2+9x+18\right)^2+2\left(x^2+9x\right)+37\)

\(=\left(x^2+9x+18\right)^2+2\cdot\left(x^2+9x+18\right)-36+37\)

\(=\left(x^2+9x+19\right)^2\)

b) Ta có: \(x^2+y^2+2x+2y+2\left(x+1\right)\left(y+1\right)+2\)

\(=\left(x^2+2x+1\right)+\left(y^2+2y+1\right)+2\left(x+1\right)\left(y+1\right)\)

\(=\left(x^2+2x+2+y^2+2y\right)^2\)