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1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
1, =4/9 x (3/7 + 2 x 4/7) - 1/9 - 3/9
= 4/9 x 1 - 1/9 - 3/9 = 0
2, = ( 22/5 x 5/22 ) x 12
= 1 x 12 = 12
\(x-\frac{1}{4}=\frac{5}{3}\)
\(\Rightarrow x=\frac{23}{12}\)
\(x:\frac{5}{11}=22\)
\(\Rightarrow x=10\)
\(\frac{2}{4}+x=1\)
\(\Rightarrow x=\frac{1}{2}\)
\(x-\frac{11}{5}=\frac{2}{5}:\frac{2}{3}\)
\(\Rightarrow x-\frac{11}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{18}{5}\)
\(a)x-\frac{1}{4}=\frac{5}{3}\)
\(\Rightarrow x=\frac{5}{3}+\frac{1}{4}=\frac{23}{12}\)
\(b)x:\frac{5}{11}=22\)
\(\Rightarrow x=22.\frac{5}{11}=10\)
\(c)\frac{2}{4}+x=1\)
\(x=1-\frac{2}{4}=\frac{1}{2}\)
\(d)x-\frac{11}{5}=\frac{2}{5}:\frac{2}{3}\)
\(\Rightarrow x-\frac{11}{5}=\frac{3}{5}\)
\(\Rightarrow x=\frac{3}{5}+\frac{11}{5}=\frac{14}{5}\)
2/3 + 3/4=17/12
9/4 + 3/5=57/20
5/24 + 1/4=11/24
3/15 - 5/35=2/35 18/27 - 2/6=1/3 37/12 - 3=1/12
11/9 x 3/22=1/6 7/13 x 13/7=1 4 x6/7=24/7
2/5 : 3/10=4/3 3/8 : 9/4=1/6 8/21 : 4/7=2/3
a. \(x-\dfrac{3}{2}=\dfrac{5}{6}\)
\(x=\dfrac{5}{6}+\dfrac{3}{2}\)
\(x=\dfrac{14}{6}=\dfrac{7}{3}\)
\(a,\dfrac{5}{9}+\dfrac{3}{8}=\dfrac{40}{72}+\dfrac{27}{72}=\dfrac{67}{72}\)
\(b,\dfrac{8}{12}-\dfrac{1}{3}=\dfrac{8}{12}-\dfrac{4}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)
\(c,\dfrac{4}{7}\times\dfrac{5}{2}=\dfrac{20}{14}=\dfrac{10}{7}\)
\(d,\dfrac{5}{11}:\dfrac{15}{22}=\dfrac{5}{11}\times\dfrac{22}{15}=\dfrac{110}{165}=\dfrac{22}{33}\)
mk ko viết đề nha:
a)=(1/2+1/2)+ (1/3+2/3)+(1/4 +3/4)+(1/5+4/5)
=(2/2 + 3/3) + (4/4 + 5/5)
=2/2 + 4/2
=6/4
À mik lm đc câu a thui nha!Nhưng k cho mik vs nhé!
3/22 x 3/11 x 22=
c1:\(\frac{3\times3\times22}{22\times11}=\frac{9}{11}\) c2:\(\frac{9}{242}\times22=\frac{9}{11}\)
( 1/2 + 1/3 ) x 2/5=
c1:\(\frac{5}{6}\times\frac{2}{5}=\frac{1}{3}\) c2:\(\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}=\frac{1}{5}+\frac{2}{15}=\frac{1}{3}\)
\(x\times\dfrac{2}{3}+x\times\dfrac{4}{3}=\dfrac{22}{5}\\ x\times\left(\dfrac{2}{3}+\dfrac{4}{3}\right)=\dfrac{22}{3}\\ x\times2=\dfrac{22}{3}\\ x=\dfrac{11}{3}\)
kìa có thg nó hỏi cái bài hình kìa giải hộ nó đi có nó spam nhiều quá