x.3,7+x.6,3=120b,x.3,7+x.6,3=120

x(3,7+6,3)=120x(3,7+6,3)=120

10x=12010x=120

x=120:10x=120:10

x=12(tm)

 (15×24-x):0.25=100 : 1/4

(15×24-x):0.25 = 400

(15x24-x) = 100

360-x =100

x=260

(8.75+1.25 +5+1) x X=20

16 x X=20

X=20 :16

X=1.25

nhớ tít

\(a,\) \(5.\left(4+6x\right)=290\)

\(4+6x=290:5\)

\(4+6x=58\)

\(6x=58-4\)

\(6x=54\)

\(x=54:6\)

\(x=9\left(tm\right)\)

Vậy ..................

\(b,x.3,7+x.6,3=120\)

\(x\left(3,7+6,3\right)=120\)

\(10x=120\)

\(x=120:10\)

\(x=12\left(tm\right)\)

Vậy ....................

c) \(\left(15.24-x\right):0,25=100:\dfrac{1}{4}\)

\(\left(360-x\right):\dfrac{1}{4}=400\)

\(360-x=400.\dfrac{1}{4}\)

\(360-x=100\)

\(x=360-100\)

\(x=260\left(tm\right)\)

Vậy ...................

a) 5. ( 4+6 . x ) = 290

( 4+6 . x ) = 290 : 5

4 + 6 . x = 58

6 .x = 58 - 4

6.x = 54

x = 54 : 6

x = 9

Bài 1:

a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)

\(=\dfrac{9}{20}-\dfrac{2}{9}\)

\(=\dfrac{41}{180}\)

b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)

\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)

\(=\dfrac{5}{6}\times\dfrac{12}{7}\)

\(=\dfrac{10}{7}\)

c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)

\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)

\(=\dfrac{7}{9}\times1\)

\(=\dfrac{7}{9}\)

Bài 2:

a) \(2\times\left(x-1\right)=4026\)

\(\left(x-1\right)=4026\div2\)

\(x-1=2013\)

\(x=2014\)

Vậy: \(x=2014\)

b) \(x\times3,7+6,3\times x=320\)

\(x\times\left(3,7+6,3\right)=320\)

\(x\times10=320\)

\(x=320\div10\)

\(x=32\)

Vậy: \(x=32\)

c) \(0,25\times3< 3< 1,02\)

\(\Leftrightarrow0,75< 3< 1,02\) ( S )

=> \(0,75< 1,02< 3\)

\(\left(84,6-2\cdot x\right):3,02=5,1\)

\(\Rightarrow84,6-2\cdot x=15,402\)

\(\Rightarrow2\cdot x=69,198\)
\(\Rightarrow x=69,198:2\)

\(\Rightarrow x=34,599\)

_____________

\(\left(15\cdot24-x\right):0,25=100:0,25\)

\(\Rightarrow\left(360-x\right):0,25=400\)

\(\Rightarrow360-x=100\)

\(\Rightarrow x-360-100\)

\(\Rightarrow x=260\)

______________

\(128\cdot x-12\cdot x-16\cdot x=5200\)

\(\Rightarrow x\cdot\left(128-12-16\right)=5200\)

\(\Rightarrow x\cdot100=5200\)

\(\Rightarrow x=5200:100\)

\(\Rightarrow x=52\)

__________________

\(5\cdot x+3,75\cdot x+1,25\cdot x=20\)

\(\Rightarrow x\cdot\left(5+3,75+1,25\right)=20\)

\(\Rightarrow10\cdot x=20\)

\(\Rightarrow x=20:10\)

\(\Rightarrow x=2\)

\(x\cdot3,7+x\cdot6,3=360:120\)

\(\Rightarrow x\cdot\left(3,7+6,3\right)=3\)

\(\Rightarrow x\cdot10=3\)

\(\Rightarrow x=\dfrac{3}{10}\)

__________________

\(x\cdot23-6\cdot23+x\cdot69=320\)

\(\Rightarrow x\cdot\left(23+69\right)=320+6\cdot23\)

\(\Rightarrow x\cdot92=458\)

\(\Rightarrow x=458:92\)

\(\Rightarrow x=\dfrac{229}{46}\)

___________________

\(\left(x+1\right)\left(x+2\right)=72\)

\(\Rightarrow x^2+2x+x+2=72\)

\(\Rightarrow x^2+3x+2=72\)

\(\Rightarrow x^2+3x+2-72=0\)

\(\Rightarrow x^2+3x-70=0\)

\(\Rightarrow x^2+10x-7x-70=0\)

\(\Rightarrow\left(x-7\right)\left(x+10\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=7\\x=-10\end{matrix}\right.\)

___________________

\(\left(x+2\right)\cdot16\cdot x=160x\)

\(\Rightarrow16x^2+32x=160x\)

\(\Rightarrow16x^2+32x-160x=0\)

\(\Rightarrow16x^2-128x=0\)

\(\Rightarrow16x\left(x-8\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=8\end{matrix}\right.\)

=-5/12-7/12-3,7-6,3

=-1-10

=-11

\(-\dfrac{5}{12}-3,7-\dfrac{7}{12}-6,3\)

\(=-\dfrac{5}{12}-\dfrac{37}{10}-\dfrac{7}{12}-\dfrac{63}{10}\)

\(=\left(-\dfrac{5}{12}-\dfrac{7}{12}\right)-\left(\dfrac{37}{10}+\dfrac{63}{10}\right)\)

\(=-\dfrac{12}{12}-\dfrac{100}{10}\)

\(=-1-10\)

\(=-11\)

3,7 = 370%

6,3 = 630%

0,34 = 34%