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Tìm x εIN biết
a) 390 - (x-8) = 168:13
b) (x-140) : 7 = 27 - 24
c) x- 6 :2 - ( 48 - 24 ) :2 :6 - 3 = 0
d) x+5.2-(32+16.3:6-15)=0
b) \(\left(x-140\right):7=27-24\)
\(\left(x-140\right):7=3\)
\(x-140=21\)
\(x=161\)
vay \(x=161\)
c) \(x-6:2-\left(48-24\right):2:6-3=0\)
\(x-3-24:2:6-3=0\)
\(x-3-2-3=0\)
\(x-8=0\)
\(x=8\)
vay \(x=8\)
d) \(x+5.2-\left(32+16.3:6-15\right)=0\)
\(x+10-\left(32+8-15\right)=0\)
\(x+10-25=0\)
\(x-15=0\)
\(x=15\)
vay \(x=15\)
a) \(390-\left(x-8\right)=168:13\)
\(390-x+8=\frac{168}{13}\)
\(x+8=390-\frac{168}{13}\)
\(x+8=\frac{5070}{13}-\frac{168}{13}\)
\(x+8=\frac{4902}{13}\)
\(x=\frac{4902}{13}-8\)
\(x=\frac{4798}{13}\)
vay \(x=\frac{4798}{13}\)
a)\(\left(x-140\right)\)\(\div\)7=27-4-3 =20\(\Rightarrow\) \(\left(x-140\right)\) =20x7=140\(\Rightarrow\) x=0
\(\Leftrightarrow\)\(5x+10-25=0\)
\(\Leftrightarrow\)\(5x=15\)
\(\Leftrightarrow\)\(x=\frac{15}{5}=3\)
x + 5 . 2 - ( 32 + 16 . 3 : 6 - 15 ) = 0
x + 10 - ( 32 + 8 - 15 ) = 0
x + 10 - 25 = 0
x - 15 = 0
x = 15
x - 6 : 2 - ( 48 - 24 ) : 2 : 6 - 3 = 0
x - 3 - 24 : 2 : 6 - 3 = 0
x - 3 - 2 = 0
x - 5 = 0
x = 5
x + 5 . 2- (32+48:6-15)=0
x+5.2-(32+8-15)=0
x+5.2-25=0
x+10=0+25=25
x=25-10
x=15
cau sau cung tuong tu nhu zay
tự làm nha
nhớ k đó
x-6:2-(48-24):2:6=0+3
x-6:2-(48-24):2:6=3
x-6:2-(48-24):2 =3 nhân6
x-6:2-(48-24):2 =18
x-6:2-48-24 =18 nhân 2
x-6:2-48-24 =36
x-6:2-48 =36+24
x-6:2-48 =60
x-6:2 =60+48
x-6:2 =108
x-6 =108:2
x-6 =54
x = 54+6
x =60