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a) \(2^{x+2}-2^2=96\)
<=> \(2^x.2^2-2^x=96\)
<=> \(2^x\left(4-1\right)=96\)
<=> \(3.2^x=96\)
<=> \(2^x=32\)
<=> \(2^x=2^5\)
<=> x = 5
b, \(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\)
\(\Rightarrow x-\left(\frac{1x}{2}+\frac{1x}{8}\right)=\frac{45}{4}\)
\(\Rightarrow x-\left(\frac{4x}{8}+\frac{1x}{8}\right)=\frac{45}{4}\)
\(\Rightarrow x-\frac{5x}{8}=\frac{45}{4}\)
\(\Rightarrow\frac{8x}{8}-\frac{5x}{8}=\frac{45}{4}\)
\(\Rightarrow\frac{3x}{8}=\frac{45}{4}\Rightarrow x=\frac{45}{4}\div\frac{3}{8}=30\)
Vậy x = 30
100 x 2 + ( 5 x 200 ) + 120 x 5
= 100 x 2 + 1000 + 120 x 5
= ( 100 x 2 ) + 1000 + ( 120 x 5 )
= 200 + 1000 + 600
= 1800
X+100+100+200=200
X+(100+100+200)=200
X+400=200
X=200-400
X=-200
\(200:25-\left(12-x\right)=4\\ 8-\left(12-x\right)=4\\ 12-x=8-4\\ 12-x=4\\ x=12-4\\ x=8\\ ---\\ \left(x-10\right).5=100-20.4\\ \left(x-10\right).5=100-80=20\\ x-10=\dfrac{20}{5}=4\\ x=4+10=14\)
a)\(200:25-\left(12-x\right)=4\)
\(\Rightarrow8-\left(12-x\right)=4\)
\(\Rightarrow12-x=8-4\)
\(\Rightarrow12-x=4\)
\(\Rightarrow x=12-4\)
\(\Rightarrow x=8\)
b) \(\left(x-10\right)\cdot5=100-20\cdot4\)
\(\Rightarrow\left(x-10\right)\cdot5=100-80\)
\(\Rightarrow\left(x-10\right)\cdot5=20\)
\(\Rightarrow x-10=4\)
\(\Rightarrow x=10+4\)
\(\Rightarrow x=14\)
1005 : 1003 = 1002
102 . 101 = 103
500200 . 50010 = 500210
105 . 102 = 107
10030 . 10010 = 10040
200100 : 20010 = 20090
10020 . 10010 = 10030
300100 . 300100 = 300200
1005 : 1003
= 1005 - 3
= 1002
102 . 101
= 102 + 1
= 103
500200 . 50010
= 500200 + 10
= 500210
105 . 102
= 105 + 2
= 107
10030 . 10010
= 10030 + 10
= 10040
200100 : 20010
= 200100 - 10
= 200190
10020 . 10010
= 10020 + 10
= 10030
300100 .300100
= 300100 + 100
= 300200
x+200+200=200+200+100
x+400=500
x=500-400
x=100
tk minh nha
X+200+200=200+200+100
X+(200+200)=500
X+400=500
X=500-400
X=100
x + 100 = 200 : 5 + 100
x + 100 = 140
x = 140 - 100
x = 40
Vậy x = 40
x + 100 = 200 : 5 + 100
x + 100 = 40 + 100
x + 100 = 140
x = 140 - 100
x = 40