h) \(=\frac{x+1}{32}\)

câu hỏi tương tự

\(\left(x+\dfrac{1}{2}\right)+\left(x+\dfrac{1}{4}\right)+\left(x+\dfrac{1}{8}\right)+\left(x+\dfrac{1}{16}\right)=1\)

\(\Leftrightarrow4x-\dfrac{1}{16}=0\)

\(\Leftrightarrow x=\dfrac{1}{64}\)

Hộ e giải bài này vs ạ

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(4x+\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)

\(4x+\left(1-\frac{1}{16}\right)=1\)

\(4x+\frac{15}{16}=1\)

\(4x=\frac{1}{16}\)

\(\Rightarrow x=\frac{1}{64}\)

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

\(\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(4x+\frac{15}{16}=1\)

\(4x=\frac{1}{16}\)

\(x=\frac{1}{16}\div4\)

\(x=\frac{1}{64}\)

Vậy ...

\(\left(\frac{1}{2}+x\right)+\left(\frac{1}{4}+x\right)+\left(\frac{1}{8}+x\right)+\left(\frac{1}{16}+x\right)=1\)

         \(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)+\left(x+x+x+x\right)=1\)

                                                                             \(\frac{15}{16}+4x=1\)

                                                                                          \(4x=\frac{1}{16}\)

                                                                                            \(x=\frac{1}{64}\)

( x + x + x + x ) + ( \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\) ) = 1

x * 4 + \(\frac{15}{16}\) = 1

x * 4 = 1 - \(\frac{15}{16}\)

x * 4 = \(\frac{1}{16}\)

x = \(\frac{1}{16}\) : 4

x = \(\frac{1}{64}\)

\(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)

\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8=\left(\dfrac{1}{7}\right)^7\times2^{16}\)

\(\left(-\dfrac{1}{7}\right)^4\times125\times5=\left(-\dfrac{1}{7}\right)^4\times5^3\times5=\left(-\dfrac{1}{7}\right)^4\times5^4\)

\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:2^3:2^{-4}=2^0\)

\(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^3\times7^3=1^3\)
 

6, \(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4\)

7,\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8\)

8,\(\left(-\dfrac{1}{7}\right) ^4\times125\times5=\left(\dfrac{1}{7}\right)^4\times5^3\times5\)

9,\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:\left[2^3\times\left(\dfrac{1}{2}\right)^4\right]\)

10, \(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times7^2\)

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

\(\Rightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(\Rightarrow4x+\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}\right)=1\)

\(\Rightarrow4x+1-\frac{1}{16}=1\)

\(\Rightarrow4x=1-1+\frac{1}{16}=\frac{1}{16}\)

\(\Rightarrow x=\frac{1}{16}:4=\frac{1}{64}\)

vậy \(x=\frac{1}{64}\)

trung bình  mỗi xe chở đc

(4500 + 4500 + 4500 + 8000 + 8000) : (3 + 2) = 5900 (tấn)

đáp số : 5900 tấn

Vào lúc: 2016-04-11 21:24:29 Xem câu hỏi

SBT = ST + hiệu

tổng sô trừ và hiệu là:(số bị trừ)

2008 : 2 = 1004

số trừ là:

(1004 - 12) : 2 = 496

trung bình  mỗi xe chở đc

(4500 + 4500 + 4500 + 8000 + 8000) : (3 + 2) = 5900 (tấn)

đáp số : 5900 tấn

Vào lúc: 2016-04-11 21:24:29 Xem câu hỏi

SBT = ST + hiệu

tổng sô trừ và hiệu là:(số bị trừ)

2008 : 2 = 1004

số trừ là:

(1004 - 12) : 2 = 496

1.2^x=4

=>2^x=2^2

=>x=2

2.2^x=8

=>2^x=2^3

=>x=3

3.2^x=16

=>2^x=2^4

=>x=4

4.2^x=32

=>2^x=2^5

=>x=5

5.2^x=64

=>2^x=2^6

=>x=6

6.2^x+1=4

=>2^x=4-1=3

=>x\(\in\phi\)

7.2^x+1=1

=>2^x=1-1=0

=>x=0

8.2^x+1=8

=>2^x=8-1=7

=>x\(\in\phi\)

9.2^x+1=16

=>2^x=16-1=15

=>x\(\in\phi\)

10.2^x+1=32

=>2^x=32-1=31

=>x\(\in\phi\)

Neu de bai sai thi cung k ung ho minh nha!Ths