Đề bài yêu cầu gì thế em?

`x^2 +4xy+ 4y^2 -9`

`= (x^2 + 2x.2y + 4y^2) -9`

`= (x+2y)^2 - 3^2`

`= (x+2y  -3)(x+2y +3)`

c

cảm ơn nha

\(2x^2-4xy+2y^2\\ =2\left(x^2-2xy+y^2\right)\\ =2\left(x-y\right)^2\)

a) 2x²-4xy+2y²
= 2x²-2xy-2xy+2y²
= 2x(x-y)-2y(x-y)
= (2x-2y)(x-y)
b) x²+4xy+4y²-9
= (x+2y)²-3²
= (x+2y-3)(x+2y+3)
c) x⁴-x³y+x-y
= x³(x-y)+(x-y)
= (x³+1)(x-y)

a, \(x^4+2x^2+1-x^2\)

= \(\left(x^2+1\right)^2-x^2\)

= \(\left(x^2+x+1\right)\left(x^2-x+1\right)\)

b, \(x^4+x^2+1\)

= \(x^4+2x^2+1-x^2\)

= .. ( như phần a )

c, \(y^4+64\)

= \(\left(y^2+8\right)\left(y^2-8\right)\)

d, \(4xy+3z-12y-xz\)

\(=4y\left(x-3\right)-z\left(x-3\right)\)

\(=\left(x-3\right)\left(4y-z\right)\)

e, \(x^2-4xy+4y^2-z^2+6z-9\)

\(=\left(x-2y\right)^2-\left(z-3\right)^2\)

g, \(x^2-4xy+5x+4y^2-10y\)

\(=\left(x^2-4xy+4y^2\right)+\left(5x-10y\right)\)

\(=\left(x-2y\right)^2+5\left(x-2y\right)\)

\(=\left(x-2y\right)\left(x-2y+5\right)\)

h, \(x^2-7x+6\)

\(=x^2-6x-x+6\)

\(=x\left(x-6\right)-\left(x-6\right)\)

\(=\left(x-6\right)\left(x-1\right)\)

i, \(x^3+5x^2+6x+2\)

\(=x^3+x^2+4x^2+4x+2x+2\)

\(=x^2\left(x+1\right)+4x\left(x+1\right)+2\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2+4x+2\right)\)

phần b là 6^4 nhé

= x^2+4xy+4y^2 -4z^2

= (x+2y)^2 -4z^2

=(x+2y-2z)(x+2y+2z)

\(=\left(x+2y-2z\right)\left(x+2y+2z\right)\)

\(x^2+4y^2-4xy-4\)

\(=\left(x^2-4xy+4y^2\right)-4\)

\(=\left(x-2y\right)^2-2^2\)

\(=\left(x-2y-2\right)\left(x-2y+2\right)\)

\(x^2+4xy-4z^2+4y^2\)

\(=x^2+4xy+4y^2-4z^2\)

\(=\left(x+2y\right)^2-4z^2\)

\(=\left(x+2y-2z\right)\left(x+2y+2z\right)\)

\(x^2+2x-15\)

\(=x^2+2x+1-16\)

\(=\left(x+1\right)^2-16\)

\(=\left(x+1-4\right)\left(x+1+4\right)\)

\(=\left(x-3\right)\left(x+5\right)\)