a) \(-12\left(x-5\right)+7\left(3-x\right)=5\)

\(-12x+60+21-7x=5\)

\(-19x=5-60-21\)

\(-19x=-76\)

\(x=4\)

vậy \(x=4\)

tương tự 

\(a,-12\left(x-5\right)+7\left(3-x\right)=5\)
     \(-12x+60+21-7x=5\)
     \(-12x-7x+81=5\)
     \(-19x=5-81\)
     \(-19x=-76\)
      \(x=-76:\left(-19\right)\)
      \(x=4\)
\(Vậyx=4\)
\(b,30\left(x+2\right)-6\left(x-5\right)-24x=100\)
     \(30x+60-6x-30-24x=100\)
     \(30x-6x-24x+60-30=100\)
     \(0x+30=100\)
\(\Rightarrow Vôlý\)
Vậy không có giá trị nào của x thỏa mãn đề bài.
\(c,-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
     \(-5x-1-\frac{1}{2}x-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
      \(-5x-\frac{1}{2}x-1-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
      \(-\frac{11}{2}x-\frac{2}{3}=\frac{3}{2}x-\frac{5}{6}\)
       \(-\frac{2}{3}+\frac{5}{6}=\frac{3}{2}x+\frac{11}{2}x\)
        \(-\frac{4}{6}+\frac{5}{6}=\frac{14}{2}x\)
         \(\frac{1}{6}=7x\)
          \(x=\frac{1}{6}:7\)

         \(x=\frac{1}{6}.\frac{1}{7}\)
         \(x=\frac{1}{42}\)
\(Vậyx=\frac{1}{42}\)
\(d,-3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)

      \(-3x+\frac{3}{2}-5x-3=-x+\frac{1}{5}\)
      \(-3x-5x+\frac{3}{2}-3=-x+\frac{1}{5}\)
      \(-8x+\frac{3}{2}-\frac{6}{2}=-x+\frac{1}{5}\)
       \(-8x-\frac{3}{2}=-x+\frac{1}{5}\)
        \(-\frac{3}{2}-\frac{1}{5}=-x+8x\)
        \(\frac{15}{10}-\frac{2}{10}=7x\)

         \(7x=\frac{13}{10}\)
          \(x=\frac{13}{10}:7\)
          \(x=\frac{13}{10}.\frac{1}{7}\)
          \(x=\frac{13}{70}\)
\(Vậyx=\frac{13}{70}\)

 

x*(x+3)=0

=> x = 0 hoặc x + 3 = 0

=> x = 0 hoặc x = -3

-12(x-5)+7(3-x)=5

=> -12x + 60 + 21 - 7x = 5

=> -19x + 81 = 5

=> -19x = -76

=> x = 4

30(x+2)-6(x-5)-24x=100 

=> 30x + 60 - 6x + 30 - 24x = 100

=> 90 = 100 (vô lí)

=> x thuộc tập hợp rỗng

Giải:

a) \(-12\left(x-5\right)+7\left(3-x\right)=5\) 

       \(-12x+60+21-7x=5\) 

                       \(-12x-7x=5-60-21\) 

                               \(-19x=-76\) 

                                     \(x=-76:-19\) 

                                     \(x=4\) 

b) \(30\left(x+2\right)-6\left(x-5\right)-24x=100\) 

       \(30x+60-6x+30-24x=100\) 

                       \(30x-6x-24x=100-60-30\) 

                                            \(0x=10\) 

Vì ko có số nào mà nhân với 0 mà đc kết quả lớn hơn 0 hay bé hơn 0 mà khi nhân với 0 ta đc kết quả 0 nên \(x\in\) ∅

\(-12\cdot\left(x-5\right)+7\cdot\left(3-x\right)=5\)

\(-12\left(x-5\right)+7\left(-x+3\right)=5\)

\(-\left(12x-12\cdot5\right)+\left(-7x+7\cdot3\right)=5\)

\(-\left(12x-60\right)+\left(-7x+21\right)=5\)

\(-12+60+-7x+21=5\)

\(-12x-7x+0+21=5\)

\(-19+81=5\)

\(\left(-19x+81\right)+\left(-81\right)=5+\left(-81\right)\)

\(-19x+81-81=5-81\)

\(-19x=76\)

\(\frac{19x}{19}=\frac{76}{19}\)

\(x=\frac{2^2\cdot19}{19}\)

\(x=2^2=4\)

\(\text{-12(x-5)+7(3-x)=5 }\)

\(-12x+60+21-7x=5\)

\(-12x-7x=5-21-60\)

\(-19x=-76\)

\(x=-76:\left(-19\right)\)

\(x=4\)

\(\text{ 30(x+2)-6(x-5)-24x=100}\)

\(30x+60-6x+30-24x=100\)

\(30x-6x-24x=100-30-60\)

\(0=10\)

\(\Rightarrow x\)ko tồn tại

\(\text{(x+1-5)+7(3-x)=5 }\)

\(x+1-5+21-7x=5\)

\(x-7x=5-21+5-1\)

\(-6x=-12\)

\(x=\left(-12\right):\left(-6\right)\)

\(x=2\)

\(\text{(x+1)+(x+3)+(x+5)+........+(x+99)=0}\)

\(\text{(x+1)+(x+3)+...+(x+99)=0}\)
tổng các số hang là\(\frac{\left(99+1\right)}{2}=50\)(số hạng)
=>\(\text{(x+1)+(x+3)+...+(x+99)=0}\)<=> \(\text{50.x+(1+3+5+..+99)=0}\)
<=>\(\text{50.x+(99+1)}\)\(.\frac{50}{2}=0\)<=> \(\text{50.x+2500=0=}\)>\(x=\frac{-2500}{50}=-50\)

chúc bạn học tốt

a) x+3=12

x=12-3

x=9

b)(x-3):2=5¹⁴:5¹²

=>(x-3):2=5²

=>(x-3):2=25

=>x-3=25.2

=>x-3=50

=>x=50+3

=>x=53

c)4x+3x=30-20:10

=>x(4+3)=30-2

=>7x=28

=>x=28:7

=>x=4

d)2x-138=2³.3²

=>2x-138=8.9

=>2x-138=72

=>2x=72+138

=>2x=210

=>x=210:2

=>x=105

a) x + 3 = 12

x = 12 - 3

x = 9

b) ( x - 3 ) : 2 = 5¹⁴ : 5¹²

( x - 3 ) : 2 = 5^14-12

( x - 3 ) : 2 = 5²

( x - 3 ) : 2 = 25

x - 3 = 50

x = 53

c) 4x + 3x = 30 - 20 : 10

7x = 28

x = 4

d) 2x - 138 = 2³ x 3²

2x - 138 = 8 x 9

2x - 138 = 72

2x = 210

x = 105

\(-12\left(x-5\right)+7\left(3-x\right)=15\)

\(-12x+60+21-7x=15\)

\(-12x-7x=15-60-21\)

\(-19x=-66\)

\(x=\frac{66}{19}\)

Vây....

b)

a) -12.(x-5)+7(3-x)=15

<=> - 12x + 60 + 21 - 7x = 15

<=> 12x + 7x = 60 + 21 - 15

<=> 19x = 66

<=> x = \(\frac{66}{19}\)

Vậy x = \(\frac{66}{19}\)

b) 30.(x+2)-6.(x-5)-24.x=100

<=> 30x + 60 - 6x + 30 - 24x = 100

<=> 0x = 10(vô lí)

VẬY x = \(\varnothing\)