Bài 2 : Tính nhanh

 a ) ( 8 , 7 x 29 +  8, 7 x 35 ) : 64

= [ 8.7 x ( 29 + 35 ) ] : 64

= [ 8.7 x 64 ] : 64

= 8.7

b ) 372 x 9 + 372

= 372 x ( 9 + 1 )

= 372 x 10

= 3720

c ) 37 x 24 + 37 x 76 + 63  x 79 + 63 x 21

= 37 x ( 24 + 76 ) + 63 x ( 79 + 21 )

= 37 x 100 + 63 x 100

= 100 x ( 37 + 63 )

= 100 x 100

= 10000

d ) 42 x 53 + 47 x 156 - 47 x 114

= 42 x 53 + 47 x ( 156 - 114 )

= 42 x 53 + 47 x 42

= 42 x ( 53 + 47 )

= 42 x 100

= 4200

hok tốt nha 

a) (8,7 x 29 + 8,7 x 35) : 64

= [8,7 x (29 + 35)] : 64

= (8,7 x 64) : 64

= 8,7 x (64 : 64)

= 8,7 x 1 = 8,7

b) 372 x 9 + 372 = 372 x (9 + 1)

= 372 x 10 = 3720

c) 37 x 24 + 37 x 76 + 63 x 79 + 63 x 21

= 37 x (24 + 76) + 63 x (79 + 21)

= 37 x 100 + 63 x 100

= (37 + 63) x 100

= 100 x 100 = 10000

d) 42 x 53 + 47 x 156 - 47 x 114

= 42 x 53 + 47 x (156 - 114)

= 42 x 53 + 47 x 42

= 42  x (53 + 47)

= 42 x 100

= 4200

1.

a) \(2^x=128\)

\(2^x=2^7\)

\(=>x=7\)

b) \(8^{x-1}=64\)

\(8^{x-1}=8^2\)

\(=>x-1=2\)

\(x=2+1\)

\(=>x=3\)

c) \(3+3^x=30\)

\(3^x=30-3\)

\(3^x=27=3^3\)

\(=>x=3\)

d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?

e) \(3^2.x=3^5\)

\(x=3^5:3^2\)

\(=>x=3^3=27\)

f) \(\left(2x-1\right)^3=343\)

\(\left(2x-1\right)^3=7^3\)

\(=>2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=8:2\)

\(=>x=4\)

\(#Wendy.Dang\) 

a,\(2^x\)=128           b,\(8^{x-1}\)=64              c,3+\(3^x\)=30           d,x+2=64

\(2^7\)=128               \(8^{x-1}\)=\(8^2\)                 \(3^x\)=30-3                  x=64-2

=>x=7              =>x-1=2                  \(3^x\)=27                      x=62

                         x=2+1=3                \(3^x\)=\(3^3\)

                                                     =>x=3

e,\(3^2\).x=\(3^5\)                             f,(2x-\(1^3\))=343

x=\(3^5\):\(3^2\)                                 2x=1+343

x=27                                     2x=344

                                               x=344:2

                                               x=172

Mk có cách giải khác nè

1/4+1/8+1/16+1/32+1/64+1/128

= 1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64+1/64-1/128

= 1/2-1/128

= 63/128

63/128

         A =    \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\)+ \(\dfrac{1}{32}\)+\(\dfrac{1}{64}\)+\(\dfrac{1}{128}\)

A\(\times\) 2 =  1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\)+ \(\dfrac{1}{32}\)+ \(\dfrac{1}{64}\) 

A \(\times\) 2 - A = 1 - \(\dfrac{1}{128}\)

A\(\times\)(2-1) = \(\dfrac{128-1}{128}\)

A           = \(\dfrac{127}{128}\)

Gọi \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\) là B

\(B=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\)

\(2\cdot B=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{1}{32}+\dfrac{1}{64}\)

\(2\cdot B-B=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{12}+\dfrac{1}{32}+\dfrac{1}{64}-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}+\dfrac{1}{64}+\dfrac{1}{128}\right)\)

\(B=1+\left(\dfrac{1}{2}-\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{4}+.....+\dfrac{1}{64}-\dfrac{1}{64}\right)-\dfrac{1}{128}\)

\(B=1+0-\dfrac{1}{128}\)

\(B=1-\dfrac{1}{128}\)

\(B=\dfrac{128}{128}-\dfrac{1}{128}\)

\(B=\dfrac{127}{128}\)

Mk chịu!

-_- mik ko bít

a: 4A=4+4^2+...+4^9

=>3A=4^9-1

=>A=(4^9-1)/3

b: 2A=1+1/2+...+1/2^7

=>A=1-1/256=255/256

c: =1-1/5+1/5-1/9+...+1/85-1/89

=1-1/89=88/89

d: =1/3(3/1*4+3/4*7+...+3/304*307)

=1/3(1-1/4+1/4-1/7+...+1/304-1/307)

=1/3*306/307=102/307

e: E=1-1/2+1/2-1/3+...+1/11-1/12

=1-1/12=11/12

g: =2/5(1-1/6+1/6-1/11+...+1/96-1/101)

=2/5*100/101=40/101