a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)

b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)

c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)

d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)

\(\frac{3.5}{8.24}=\frac{3.5}{2^3.2^3.3}=\frac{1.5}{8.8.1}=\frac{5}{64}\)

\(\frac{2.14}{7.8}=\frac{2.7.2}{7.2^3}=\frac{1.7}{7.2}=\frac{1}{2}\)

\(\frac{3.7.11}{22.9}=\frac{1.7.11}{11.2.3}=\frac{1.7.1}{1.2.3}=\frac{7}{6}\)

\(\frac{8.5-8.2}{16}=\frac{8\left(5-2\right)}{8.2}=\frac{8.3}{8.2}=\frac{1.3}{1.2}=\frac{3}{2}\)

\(\frac{11.4-11}{2-13}=\frac{11\left(4-1\right)}{-11}=\frac{11.3}{-11}=-3\)

Bài 17 (Sgk Toán 6 Trang 15)

a) 3.5/8.24=3.5:3/8.24:3=5/8.8=5/64.

b) 2.14/7.8=2.2.7/7.2^3=2.7/7.4=1/2.

c) 3.7.11/22.9=3.7.1/12.11.3^2=7/2.3=76.

d)  8.5−8.2/16=(8.5−8.2):8/16:8=5−2/2=32.

e) 11.4−11/2−13=11.4−11/−11=(11.4−11):11/−11:11=4−1/−1=−3/1=-3

\(\dfrac{-63}{72}=\dfrac{-7}{8}\)

\(\dfrac{20}{-140}=\dfrac{-1}{7}\)

\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)

\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)

\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)

\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)

Ta có: \(\dfrac{8.5-8.2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{8.3}{16}=\dfrac{3}{2}\) 

           \(\dfrac{11.4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{11.3}{-11}=-3\)

D

B

thank

a) \(\dfrac{22}{55}=\dfrac{2}{5}\)

b) \(\dfrac{-63}{81}=\dfrac{-7}{9}\)

c) \(\dfrac{2.14}{7.8}=\dfrac{2.7.2}{7.2.2.2}=\dfrac{1}{2}\)

d) \(\dfrac{49+7.49}{49}=\dfrac{49.\left(7+1\right)}{49}=\dfrac{49.8}{49}=8\)

\(\dfrac{22}{55}=\dfrac{2}{5}\)                                          \(\dfrac{-63}{81}=\dfrac{-7}{9}\)

\(\dfrac{2.14}{7.8}=\dfrac{28}{56}=\dfrac{1}{2}\)                             \(\dfrac{49+7.49}{49}=8\)

a) \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{0,3\cdot10}{16\cdot10}=\dfrac{3}{160}\)

b) \(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\cdot\left(5-1\right)}{-17}=\dfrac{1\cdot4}{-1}=-4\)

a)

\(\dfrac{8\cdot5-8\cdot2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{3}{2}\)

b)

\(\dfrac{17\cdot5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{4}{-1}=-4\)

\(\dfrac{3.5}{8.24}=\dfrac{3.5}{8.3.8}=\dfrac{5}{64}\)

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