\(a-68=\left(3\frac{10}{11}-4\right):\left(\frac{2121}{2222}-1\right):\left(\frac{33333}{343434}-1\right)\)

\(a-68=\left(\frac{43}{11}-4\right):\left(\frac{-1}{22}\right):\left(\frac{-310101}{343434}\right)\)

\(a-68=\frac{-1}{11}.\frac{-22}{1}.\frac{-343434}{310101}\)
\(a-68=\frac{1}{11}.\frac{22}{1}.\frac{343434}{310101}.\left(-1\right)\)

\(a-68=\frac{-686868}{310101}\)

          \(a=\frac{-686868}{310101}+68\)

          \(a=\frac{-20400000}{310101}\)

Vậy  \(a=\frac{-20400000}{310101}\)

cảm ơn bạn Lam Ngo Tung

\(x+7\dfrac{4}{5}=9\dfrac{7}{15}\)

\(=>x+\dfrac{39}{5}=\dfrac{142}{15}\)

\(=>x=\dfrac{142}{15}-\dfrac{39}{5}=\dfrac{142}{15}-\dfrac{117}{15}\)

\(=>x=\dfrac{25}{15}=\dfrac{5}{3}\)

___________

\(x-4\dfrac{9}{11}=\dfrac{2121}{2222}\)

\(=>x-\dfrac{53}{11}=\dfrac{21}{22}\)

\(=>x=\dfrac{21}{22}+\dfrac{53}{11}=\dfrac{21}{22}+\dfrac{106}{22}\)

\(=>x=\dfrac{127}{22}\)

\(x+7\dfrac{4}{5}=9\dfrac{7}{15}\)

\(x=9\dfrac{7}{15}-7\dfrac{4}{5}\)

\(x=\left(9-7\right)+\left(\dfrac{7}{15}-\dfrac{4}{5}\right)\)

\(x=2\dfrac{-1}{3}=\dfrac{5}{3}\)

\(x=\dfrac{2121:101}{2222:101}+4\dfrac{9}{11}\)

\(x=\dfrac{21}{22}+4\dfrac{18}{22}\)

\(x=\dfrac{21+4\cdot22+18}{22}=\dfrac{127}{22}\)

a ) \(x+7\frac{4}{5}=9\frac{7}{15}\)

\(x+\frac{39}{5}=\frac{142}{15}\)

\(x=\frac{142}{15}-\frac{39}{5}\)

\(x=\frac{5}{3}\)

b ) \(x-4\frac{9}{11}=\frac{2121}{2222}\)

\(x-\frac{53}{11}=\frac{21}{22}\)

\(x=\frac{21}{22}+\frac{53}{11}\)

\(x=\frac{127}{22}\)

ai đúng trả lời trước mik sẽ kick cho ^^

\(x+7\frac{4}{5}=9\frac{7}{15}\)

\(x=9\frac{7}{15}-7\frac{4}{5}\)

\(x=9\frac{7}{15}-7\frac{12}{15}\)

\(x=-2\frac{1}{3}\)

\(x-4\frac{9}{11}=\frac{2121}{2222}\)

\(x-4\frac{9}{11}=\frac{101.21}{101.22}\)

\(x-\frac{53}{11}=\frac{21}{22}\)

\(x=\frac{21}{22}+\frac{53}{11}\)

\(x=\frac{127}{22}=5\frac{17}{22}\)

a) x + \(7\frac{4}{5}\)= \(9\frac{7}{15}\)

x + 39/5 = 95/15

x = 95/15 - 39/5 

x = 95/15 - 127/15

x = -32/15

b) Tương tự

điểm âm của mik chỉ còn 158 nữa thôi, các bn giúp mik nha

Khi nào hết âm mik sẽ ra câu hỏi và giúp lại các bn

Cảm ơn trc~