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`#3107.101107`

a,

\(\text{A = }\left\{x\in R\text{ | }\left(2x-x^2\right)\left(3x-2\right)=0\right\}\)

`<=> (2x - x^2)(3x - 2) = 0`

`<=>`\(\left[{}\begin{matrix}2x-x^2=0\\3x-2=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x\left(2-x\right)=0\\3x=2\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\2-x=0\\x=\dfrac{2}{3}\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\x=2\\x=\dfrac{2}{3}\end{matrix}\right.\)

Vậy, `A = {0; 2; 2/3}`

b,

\(\text{B = }\left\{x\in R\text{ | }2x^3-3x^2-5x=0\right\}\)

`<=> 2x^3 - 3x^2 - 5x = 0`

`<=> x(2x^2 - 3x - 5) = 0`

`<=>`\(\left[{}\begin{matrix}x=0\\2x^2-3x-5=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\2x^2-2x+5x-5=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\\left(2x^2-2x\right)+\left(5x-5\right)=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\2x\left(x-1\right)+5\left(x-1\right)=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\\left(2x+5\right)\left(x-1\right)=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\2x+5=0\\x-1=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{2}\\x=1\end{matrix}\right.\)

Vậy, `B = {-5/2; 0; 1}.`

c,

\(\text{C = }\left\{x\in Z\text{ | }2x^2-75x-77=0\right\}\)

`<=> 2x^2 - 75x - 77 = 0`

`<=> 2x^2 - 2x + 77x - 77 = 0`

`<=> (2x^2 - 2x) + (77x - 77) = 0`

`<=> 2x(x - 1) + 77(x - 1) = 0`

`<=> (2x + 77)(x - 1) = 0`

`<=>`\(\left[{}\begin{matrix}2x+77=0\\x-1=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}2x=-77\\x=1\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=-\dfrac{77}{2}\\x=1\end{matrix}\right.\)

Vậy, `C = {-77/2; 1}`

d,

\(\text{D = }\left\{x\in R\text{ | }\left(x^2-x-2\right)\left(x^2-9\right)=0\right\}\)

`<=> (x^2 - x - 2)(x^2 - 9) = 0`

`<=>`\(\left[{}\begin{matrix}x^2-x-2=0\\x^2-9=0\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x^2+x-2x-2=0\\x^2=9\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}\left(x^2+x\right)-\left(2x+2\right)=0\\x^2=\left(\pm3\right)^2\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x\left(x+1\right)-2\left(x+1\right)=0\\x=\pm3\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}\left(x-2\right)\left(x+1\right)=0\\x=\pm3\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x-2=0\\x+1=0\\x=\pm3\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=2\\x=-1\\x=\pm3\end{matrix}\right.\)

Vậy, `D = {-1; -3; 2; 3}.`

Lời giải:

$A=\left\{12; 18; 24;30\right\}$

Bài 40:

a) A = \(\left\{11;12;13;14;15\right\}\)

b) B = \(\left\{1;2;3;4;5;6\right\}\)

c) C = \(\left\{12;13;14;15;16;17;18;19\right\}\)

d) D = \(\left\{1;2;3;4;5;6;7;8;9;10\right\}\)

Câu 41:

a) A = \(\left\{0;1;2;3;4;5\right\}\)

b) B = \(\left\{1;2;3;4;5\right\}\)

c) C = \(\left\{0;1;2;3;4;5;6;7\right\}\)

d) D = \(\left\{205;206;207;208\right\}\)

e) E = \(\left\{1200;1201;1202;1203;1204;1205\right\}\)

g) G = \(\left\{250;251;252;253;254\right\}\)

Bài 42: 

a) A = \(\left\{0;1;2;3;4;5;6;7\right\}\)

b) B = \(\left\{10;11;12;13;14\right\}\)

c) C = \(\left\{0;1;2;3;4;5;6\right\}\)

d) D = \(\left\{8;9;10;11;12;13\right\}\)

e) E = \(\left\{1;2;3;4\right\}\)

f) F = \(\left\{1;2;3;4;5;6;7\right\}\)

g) G = \(\left\{17;18;19;20;21\right\}\)

h) H = \(\left\{8;9;10;11;12;13\right\}\)

Bài 43: ( bạn không viết rõ đề bài nên mình viết 2 cách ra nhé )

a) A = \(\left\{0;1;2;3;4;5;...;2298;2299;2300\right\}\)

    A = \(\left\{x\in N|x\le2300\right\}\)

b) B = \(\varnothing\) ( B thuộc tập hợp rỗng )

    B = \(\left\{x\in N|14< x< 15\right\}\)

c) C = \(\left\{0;1;2;3;4\right\}\)

    C = \(\left\{x\in N|x\le4\right\}\)

d) D = \(\left\{1;2;3;4;5;6;...;143;144\right\}\)

    D = \(\left\{x\inℕ^∗|x< 145\right\}\)

e) E = \(\left\{7;8;9;10;11;12\right\}\)

    E = \(\left\{x\in N|6< x\le12\right\}\)

g) G = \(\left\{1226;1228;1230;1232;1234\right\}\)

    G = \(\left\{x\in N\right\}chẵn|1225< x\le1234\)

Bài 44:

a) A = \(\left\{0;1;2;3;4;5;...;49;50\right\}\)

    A = \(\left\{x\in N|x\le50\right\}\)

b) B = \(\varnothing\) ( B thuộc tập hợp rỗng ) 

    B = \(\left\{x\in N|8< x< 9\right\}\)

c) C = \(\left\{0;1;2;3;4;5;6\right\}\)

    C = \(\left\{x\in N|x\le6\right\}\)

d) D = \(\left\{1;2;3;4\right\}\)

    D = \(\left\{x\inℕ^∗|x< 5\right\}\)

e) E = \(\left\{8;9;10;11;12;13;14\right\}\)

    E = \(\left\{x\in N|7< x\le14\right\}\)

Bài 45: 

a) B = \(\left\{0;1;2;3;4;5\right\}\)

    B = \(\left\{x\in N|x\le5\right\}\)

b) thuộc tập hợp B thì: 

\(5\in B\)

\(4\in B\)

\(0\in B\)

\(6\notin B\)

\(1\in B\)

\(\dfrac{1}{2}\notin B\)

Chúc bạn học tốt

Lần sau bạn gửi vài bài chứ như vầy nhiều lắm nha.

F = ∅

`F = {x \in N` `| 0 \div x = 2}`

Bạn xem lại đề, `0` không thể chia được và nhân thì cũng không thể `=2` được.

Giúp với ạ

a) A = {22; 24;26;28;30;32;34;36;38}

b) Số phần tử của B là: 114

Lời giải:
a. $G=\left\{1;2;3;4;5;6\right\}$

b. $H=\left\{3;4;5;6;7;8\right\}$

c. $I=\left\{13;14;15;16;17;18\right\}$

d. $K=\left\{65; 70; 75;80;85;90\right\}$

Đề sai nha bạn, mk sửa lại G={n\(\in\)N|0<n<7}

a) G={1; 2; 3; 4; 5; 6}

b) H={3; 4; 5; 6; 7; 8}

c) I={13; 14; 15; 16; 17; 18}

d) K={65; 70; 75; 80; 85; 90}