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DẠ CẢM ƠN NHIỀU Ạ ^^❤

2^x   = 32

2^x = 2⁵ 

\(\Rightarrow x=5\)

2^x = 32 mà 32 = 2⁵ => 2^x = 2⁵ => x = 5

Cái này bạn áp dụng cộng dãy số cách đều là ra à

Số số hạng là: \(\dfrac{58-1}{1}+1=58\left(số\right)\)

Tổng của dãy là; \(\dfrac{58\left(58+1\right)}{2}=29\cdot59=1711\)

1. She got the job as a secretary without being able to use a computer. 2. Our teachers don't force us to go to extra classes. 3. I used to be strong when I was young. 4. They didn't use to go out much before they bought a motorbike. 5. I am used to wearing contact lenses. 6. He spent two hours fixing his car. 7. This motorbike cost 500 dollars. 8. She is interested in walking in the rain. 9. It's no use talking without doing anything. 10. I am going to have my car fixed by a man. 11. What is the price of this dress? 12. She'd rather Vietnamese food than American one. 13. My dad'd rather 'do' than talk. 14. You'd better try new things in order to know your ability. 15. There's no point in persuading him to go with you. 16. Her English is too bad for her to work as an interpreter. 17. This car is too expensive for me to buy. 18. You don't learn hard enough. 19. It's foolish of him to say that. 20. You'd better spend more time learning English.

a/ Tam giác AMN cân tại A (gt). \(\Rightarrow\) \(\widehat{AMN}=\widehat{ANM};AM=AN.\)

Xét tam giác AMB và tam giác ANC có:

+ AM = AN (cmt).

+ \(\widehat{AMB}=\widehat{ANC}\left(\widehat{AMN}=\widehat{ANM}\right).\)

+ MB = NC (gt).

\(\Rightarrow\) Tam giác AMB = Tam giác ANC (c - g - c).

\(\Rightarrow\) AB = AC (cặp cạnh tương ứng).

Xét tam giác ABC có: AB = AC (cmt).

\(\Rightarrow\) Tam giác ABC cân tại A.

b/ Tam giác ABC cân tại A (cmt) \(\Rightarrow\) \(\widehat{ABC}=\widehat{ACB}.\)

Mà \(\widehat{ABC}=\widehat{MBH;}\widehat{ACB}=\widehat{NCK}\text{​​}\) (đối đỉnh).

\(\Rightarrow\) \(\widehat{MBH}=\widehat{NCK}.\)

Xét tam giác MBH và tam giác NCK \(\left(\widehat{BHM}=\widehat{CKN}=90^o\right)\)có:

+ MB = NC (gt).

+ \(\widehat{MBH}=\widehat{NCK}\left(cmt\right).\)

\(\Rightarrow\) Tam giác MBH = Tam giác NCK (cạnh huyền - góc nhọn).

c/ Tam giác MBH = Tam giác NCK (cmt).

\(\Rightarrow\) \(\widehat{BMH}=\widehat{CNK}\) (cặp góc tương ứng).

Xét tam giác OMN có: \(\widehat{NMO}=\widehat{MNO}\) (do \(\widehat{BMH}=\widehat{CNK}\)).

\(\Rightarrow\) Tam giác OMN tại O.

\(3x:9=3\)

\(\Rightarrow x=\frac{3\cdot9}{3}\)

\(\Rightarrow x=9\)

Vậy x = 9

=> 3x=9.3=18 

=> x=18:3=6

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\(\left|2x-3\right|=3-2x\)

\(ĐK:x\le\dfrac{3}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3-2x\\3-2x=3-2x\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\0=0\left(đúng\right)\end{matrix}\right.\)

Vậy \(S=\left\{x\in R;x=\dfrac{3}{2}\right\}\)

1.D       2.C