Lời giải :

\(x^2-2014xy-2016xz+\left(2015^2-1\right)yz\)

\(=x^2-2014xy-2016xz+\left(2015-1\right)\left(2015+1\right)yz\)

\(=x^2-2014xy-2016xz+2014\cdot2016\cdot yz\)

\(=x\left(x-2014y\right)-2016z\left(x-2014y\right)\)

\(=\left(x-2014y\right)\left(x-2016z\right)\)

1/ \(\left(a-b\right)\left(a^2+3ab+b^2\right)+\left(a+b\right)^3+ab\left(b-a\right)=\left(a^2+2ab+b^2+ab\right)\left(a-b\right)+\left(a+b\right)^3+ab\left(b-a\right)\)= \(\left(a^2+2ab+b^2\right)\left(a-b\right)+\left(a+b\right)ab+\left(a-b\right)^3-ab\left(a-b\right)\)

= \(\left(a+b\right)^2\left(a-b\right)+\left(a+b\right)^3\)

= \(\left(a+b\right)^2\left(a-b+a+b\right)=2a\left(a+b\right)^2\)

k mình nhé!

x² - 2014xy - 2016xz + (2015² - 1)yz

= x² - 2014xy - 2016xz + (2015 - 1)(2015 + 1)yz

= x² - 2014xy - 2016xz + 2014.2016.yz

= (x² - 2014xy) - (2016xz - 2014.2016.yz)

= x(x - 2014y) - 2016z(x - 2014y)

= (x - 2014y)(x - 2016z)

#TT

\(2\left(x-z\right)+xy-yz\)

\(=2\left(x-z\right)+y\left(z-z\right)\)

\(=\left(x-z\right)\left(2+y\right)\)

xy+yz-2*(x+2)

\(2\left(xy+yz+zx\right)-x^2-y^2-z^2\)

\(2xy+2yz+2zx-x^2-y^2-z^2\)

\(-\left(x^2+y^2+z^2-2xy-2yz-2xz\right)\)

\(-\left(x+y+z\right)^2\)