$[27\cdot(-67)+33\cdot(-27)]:(-30)$

$=[(-27)\cdot67+33\cdot(-27)]:(-30)$

$=[-27\cdot(67+33)]:(-30)$

$=(-27\cdot100):(-30)$

$=-2700:(-30)$

$=2700:30$

$=90$

b) 3x⁴-3x³+9x³-9x²-24x²+24x-48x+48

=3x³(x-1)+9x²(x-1)-24x(x-1)-48(x-1)

=(x-1)(3x³+9x²-24x-48)

=3(x-1)(x³+3x²-8x-16)

uầy có 1 mk chị gửi câu hỏi thpt thôi  ư : v

3x²-27

a) x⁴ - 10x³ - 15x² + 20x + 4

= x⁴ + 2x³ - 12x³ - 24x² + 9x² + 18x + 2x + 4

= x³(x + 2) - 12x²(x + 2) + 9x(x + 2) + 2(x + 2)

= (x + 2)(x³ - 12x² + 9x + 2)

b)

2x⁴ - 5x³ - 27x² + 25x + 50

= 2x³(x - 2) - x²(x - 2) - 25x(x - 2) - 25(x - 2)

= (x - 2)(2x³ - x² - 25x - 25)

c)\(3x^4+6x^3-33x^2-24x+48\)

\(=3\left(x^4+2x^3-11x^2-8x+16\right)\)

\(=3\left(x^4-x^3-4x^2+3x^3-3x^2-12x-4x^2+4x+16\right)\)

\(=3\left(x^2\left(x^2-x-4\right)+3x\left(x^2-x-4\right)-4\left(x^2-x-4\right)\right)\)

\(=3\left(x^2+3x-4\right)\left(x^2-x-4\right)\)

\(=3\left(x^2-x+4x-4\right)\left(x^2-x-4\right)\)

\(=3\left[x\left(x-1\right)+4\left(x-1\right)\right]\left(x^2-x-4\right)\)

\(=3\left(x-1\right)\left(x+4\right)\left(x^2-x-4\right)\)

Bài 1 :

\(3^{22}-9^{10}-27^6=3^{22}-\left(3^2\right)^{10}-\left(3^3\right)^6=3^{22}-3^{20}-3^{18}=3^{18}.\left(3^4-3^2-1\right)=3^{18}.71\)chia hết cho 71 (đpcm).

a) 17x + 33x = 100

<=> 50x = 100

<=> x = 2

Vậy x = 2

b) 23x + 15 ( x + 7) = 105

<=> 23x + 15x + 105 = 105

<=> 38x = 0

<=> x = 0

Vậy x = 0

c) 32 (x - 11) + 4x = 152

<=> 32x - 352 + 4x = 152

<=> 36x = 504

<=> x = 14

Vậy x = 14

d) 51 ( 3x + 5) - 406 = 22 (3x +50)

<=> 153x + 255 - 406 = 66x + 1100

<=> 87x = 1251

<=> x = \(\frac{1251}{87}\)

Vậy x = \(\frac{1251}{87}\)

Học tốt nhá :))

Bài làm :

\(a,17x+33x=100\)

\(\left(17+33\right)x=100\)

\(50x=100\)

\(x=2\)

\(b,23x+15\left(x+7\right)=105\)

\(23x+15x+105=105\)

\(38x=0\)

\(x=0\)

\(c,32\left(x-11\right)+4x=152\)

\(32x-352+4x=152\)

\(36x=504\)

\(x=14\)

\(d,51\left(3x+5\right)-406=22\left(3x+50\right)\)

\(153x+255-406=66x+1100\)

\(153x-66x=1100+406-255\)

\(87x=1251\)

\(x=\frac{1251}{87}\)

Học tốt

Đáp án D