BCNN(15;54)=270

BC(15;54)=B(270)={270;540;810}

BCNN(15;54)=270

BC(15;54)=B(270)={270;540;810}

Ủng hộ mình nhé

a, - 128 . (-25+89) + 128.(89-125)

   = 128 . - (-25 +89) +  128 .  (89 - 125)

   =  128 . [-(-25+89)+(89 - 125)]

   = 128. (25+89+89-125)

   = 128 . (89.2+-100)=128.78=(120+8).(70+8)= 8.190=1520

ai làm hộ mình câu b với

46.(54-15)-54.(46+15)

=46.54-46.15-54.46+54.15

bạn bấm máy tính ra kết quả nhé

ket qua la 1500

  ( - 15) . (-54) + (-15) . (-46)

= (-15) . [ ( -54) + (-46)]

= (-15). (-100)

= 1500

\(\frac{10}{15}=\frac{34}{51}=\frac{36}{54}\)

\(\frac{15}{20}=\frac{51}{68}=\frac{54}{72}\)

a) \(...=\dfrac{5}{6}-\dfrac{4}{15}=\dfrac{75}{90}-\dfrac{24}{90}=\dfrac{51}{90}\)

b) \(...=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{5}{10}-\dfrac{2}{10}=\dfrac{3}{10}\)

\(\dfrac{25}{30}\) - \(\dfrac{4}{15}\) = \(\dfrac{5}{6}\) - \(\dfrac{4}{15}\) = \(\dfrac{17}{30}\)

\(\dfrac{27}{54}\) - \(\dfrac{3}{15}\) = \(\dfrac{1}{2}\) - \(\dfrac{1}{5}\) = \(\dfrac{3}{10}\) 

Bạn tự QĐMS nhé

\(3)1579-(53+1579)-(53) \)

\(=1579-53-1579+53\)

\(=(1579-1579)-(-53+53)\)

\(=0-0\)

\(=0\)

\(4)2001-15+54-2001-54\)

\(=(2001-2001)+(54-54)-15\)

\(=0+0-15\)

\(=0-15\)

\(=-15\)

a)

\(15+27+9+85+73\)

\(=\left(15+85\right)+\left(27+73\right)+39\)

\(=200+39\)

\(=329\)

b)

\(54.36+54.27+54.37\)

\(=54\left(36+27+37\right)\)

\(=54.100\)

\(=5400\)

c)

\(168-3^7:3^4+2013^0\)

\(=168-3^3+1\)

\(=168-27+1\)

\(=142\)

d)

\(3^4.15+81.26+27.59.3\)

\(=81.15+81.26+81.59\)

\(=81.\left(15+26+59\right)\)

\(=81.100\)

\(=8100\)

Tính giá trị của các biểu thức sau :

a.15 + 27 + 39 + 85 + 73

= ( 15 + 85 ) + ( 27 + 73 ) + 39

= 100 + 100 + 39

= 200 + 39

= 239

b. 54 .36 + 54 . 27 + 54 . 37

= 54 . ( 36 + 27 + 37 )

= 54 . 100

= 5400

c.168 - 3⁷ : 3⁴ + 2013⁰

= 168 - 3³ + 1

= 168 - 27 + 1

= 141 + 1

= 142

đ. 3⁴ . 15 + 81 . 26 + 27 . 59 . 3

= 3⁴ . 15 + 3⁴ . 26 + 3⁴ . 59

= 3⁴ . ( 15 + 26 + 59 )

= 81 . 100

= 8100