a, 1/2

b, 6

\(\Leftrightarrow3^{x-1}\left(1+3+3^2\right)=39\\ \Leftrightarrow3^{x-1}\cdot13=39\\ \Leftrightarrow3^{x-1}=3=3^1\\ \Leftrightarrow x-1=1\Leftrightarrow x=2\)

\(\Leftrightarrow3^x\cdot\dfrac{13}{3}=39\)

\(\Leftrightarrow x=2\)

Đặt A = 1.2 + 2.3 + 3.4 + ... + 38.39 + 39.40

=> 3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 38.39.(40 - 37) + 39.40.(41 - 38)

           = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 38.39.40 - 37.38.39 + 39.40.41 - 38.39.40

           = 39.40.41 = 63960

=> A = 63960 : 3 = 21320

1 x 40 x (2 x 2) + (3x2) + (4x2) +...+ ( 39 x 2)

1 x 40 x (2 + 3 + 4 + .... + 39) x 2

40    x 779 x 2

31160 x 2

62320

k nha

23 x ( 12 x X + 39 ) = 23 + 40 x 115

<=> 23 x ( 12 x X + 39 ) = 4623

<=> 12 x X + 39 = 4623 : 23

<=> 12 x X + 39 = 201

<=> 12 x X = 201 - 39

<=> 12 x X = 162

=> X = 162 : 12

=> X = 13,5

hok tốt nha

x =13,5

nha

k đi

bạn vũ ngọc hải k đúng mình với

Ta có :

\(S=1.2+2.3+...+39.40\)

\(\Rightarrow3S=1.2.3+2.3.3+....+39.40.3\)

\(\Rightarrow3S=1.2.\left(3-0\right)+2.3.\left(4-1\right)+....+39.40.\left(41-38\right)\)

\(\Rightarrow3S=1.2.3-0.1.2+2.3.4-1.2.3+.....+39.40.41-38.39.40\)

\(\Rightarrow3S=39.40.41\)

\(\Rightarrow S=\frac{38.39.40}{3}=21320\)

\(x=\dfrac{11}{3}-\dfrac{3}{4}=\dfrac{35}{12}\)

\(-39-x=-3-16\)

\(-39-x=\left(-3\right)+\left(-16\right)\)

\(-39-x=-19\)

\(x=\left(-39\right)-\left(-19\right)\)

\(x=-20\)

-39-x=-3-16

=>-39-x=-19

=>x=-20