a)\(12-\left[25+\left(6+3\right)^2\right]\)

\(=12-\left[25+9^2\right]\)

\(=12-\left[25+81\right]\)

\(=12-106\)

\(=\left(-94\right)\)

b) \(315-\left(8^6\div8^4-12.3+7+7^3\right)\)

\(=316-\left(8^2-36+7+343\right)\)

\(=316-\left(64-43+343\right)\)

\(=316-\left(21+343\right)\)

\(=316-364\)

\(=\left(-48\right)\)

c) \(-81-108\)

 \(=-\left(81+108\right)\)

\(=\left(-189\right)\)

d) \(-13-91\)

\(=-\left(13+91\right)\)

\(=\left(-104\right)\)

1)...=135+65+360+40+24=200+400+24=624

2)...=(8.125).(4.25)=1000.100=100000

4)...= (467+433)+(238+762)+3465=990+1000+3465=5455

5)...=129.(172-73+1)=129.100=12900

6)...=205-(1200-(16-6)³):40=205-(1200-1000):40=205-200:40=205-5=200

Trả lời chi tiết giúp mình đc ko

a, 24 x 91 + 6 x 47 - 24 x 38

= (24 x 91 - 24 x 38) + 6 x 47

= 24 x (91 - 38) + 6 x 47

= 24 x 53 + 6 x 47

= 1272 + 282

= 1554

a) 24 x 91 + 6 x 47 - 24 x 38

= 24 x (91 - 38) + 6 x 47

= 24 x 53 + 6 x 47

= 6 x 4 x 53 + 6 x 47

= 6 x 212 + 6 x 47

= 6 x (212 + 47)

= 6 x 259

= 1554

a) \(=\left(\left(-\frac{1}{4}-\frac{5}{3}\right)+\frac{7}{33}\right)-\left(-\frac{15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)

\(=\left(-\frac{23}{12}+\frac{7}{33}\right)+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)

\(=\left(-\frac{23}{12}+\frac{15}{12}\right)+\left(\frac{9}{33}-\frac{6}{11}\right)+\frac{48}{49}\)

\(=-\frac{2}{3}-\frac{3}{11}+\frac{48}{49}\)

\(=\frac{65}{1617}\)

b) \(=\frac{11}{125}+\left(-\frac{17}{18}+\frac{4}{9}\right)+\left(-\frac{5}{7}+\frac{17}{14}\right)\)

\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)

\(=\frac{11}{125}\)

tính từng cái là đc

a: =125-24-75

=50-24

=26

Ta có:

A= 1+2-3-4+5+6-7-8+...-2011-2012+2013+2014 

= (1+2-3-4)+(5+6-7-8)+...(2009+2010-2011-2012)+(2013+2014)

Ta thấy từ 1 đến 2012 có: \(x = {2012-1 \over 1}\)+1=2012(số)

Ta nhóm các số hạng kia trong tổng A và bớt đi tổng 2013+2014, mỗi nhóm là 4 số hạng liên tiếp

=> Có số nhóm là: 2012:4=503(nhóm)

Ta lại có: 

A= (1+2-3-4)+(5+6-7-8)+...(2009+2010-2011-2012)+(2013+2014)

=(-4)+(-4)+...+(-4)+(2013+2014)

(503 số hạng -4)

=(-4).503+(2013+2014)

=(-2012)+4027

=2015

Vậy A=2015

Ta có : 1+2-3-4+5+6-7-8+...-2011-2012+2013+2014
=(1+2)+(-3-4+5+6)+(-7-8+9+10)+...+(-2011-2012+2013+2014)
=3+(4+4+...+4)(có 503 số 4)
=3+4*503
=3+2012
=2015

A = 6 -2/3 + 1 /2 - 5 -5/3 +3/2 -3 + 7/3 - 5/2 

   = (6 - 5 - 3) - ( 2/3 -5/3 + 7/3 ) + ( 1/2 +3/2 - 5/2)

    = -2 + 0 -1/2 = -5/2

ko hiểu

`@` `\text {Ans}`

`\downarrow`

`a.`

`A=(1/2-7/13-1/3)+(-6/13+1/2+1 1/3)`

`= 1/2 - 7/13 - 1/3 - 6/13 + 1/2 + 1 1/3`

`= (1/2 + 1/2) + (-7/13 - 6/13) + (-1/3 + 1 1/3) `

`= 1 - 1 + 1`

`= 1`

`b.`

`B=0,75+2/5+(1/9-1 1/2+5/4)`

`= 3/4 + 2/5 + 1/9 - 3/2 + 5/4`

`= (3/4+5/4)+ 1/9 + 2/5 - 3/2`

`= 2 + 1/9 - 11/10`

`= 19/9 - 11/10`

`= 91/90`

`c.`

`(-5/9).3/11+(-13/18).3/11`

`= 3/11*[(-5/9) + (-13/18)]`

`= 3/11*(-23/18)`

`= -23/66`

`d.`

`(-2/3).3/11+(-16/9).3/11`

`= 3/11* [(-2/3) + (-16/9)]`

`= 3/11*(-22/9)`

`= -2/3`

`e.`

`(-1/4).(-2/13)-7/24.(-2/13)`

`= (-2/13)*(-1/4-7/24)`

`= (-2/13)*(-13/24)`

`= 1/12`

`f.`

`(-1/27).3/7+(5/9).(-3/7)`

`= 3/7*(-1/27 - 5/9)`

`= 3/7*(-16/27)`

`= -16/63`

`g.`

`(-1/5+3/7):2/11+(-4/5+4/7):2/11`

`=[(-1/5+3/7)+(-4/5+4/7)] \div 2/11`

`= (-1/5+3/7 - 4/5 + 4/7) \div 2/11`

`= [(-1/5-4/5)+(3/7+4/7)] \div 2/11`

`= (-1+1) \div 2/11`

`= 0 \div 2/11 = 0`

Bài 1:

\(a.8,32+14,76+5,24=8,32+\left(14,76+5,24\right)\)

\(=8,32+20=28,32\)

\(b,16,88+9,76+3,12=\left(16,88+3,12\right)+9,76\)

\(=20+9,76=29,76\)

\(c,\left(\dfrac{2}{5}+\dfrac{7}{9}\right)+\dfrac{3}{5}=\left(\dfrac{2}{5}+\dfrac{3}{5}\right)+\dfrac{7}{9}\)

\(=1+\dfrac{7}{9}=\dfrac{16}{9}\)

\(d,\dfrac{19}{11}+\left(\dfrac{8}{13}+\dfrac{3}{11}\right)\)

\(=\left(\dfrac{19}{11}+\dfrac{3}{11}\right)+\dfrac{8}{13}=\dfrac{22}{11}+\dfrac{8}{13}\)

\(=2+\dfrac{8}{13}=\dfrac{34}{13}\)

Ko làm bài ah