tick cho mình rồi mình làm cho

\(\frac{25-x}{995}+\frac{21-x}{997}+\frac{17-x}{999}=\frac{11-x}{334}\)

\(\Rightarrow\frac{25-x}{995}+2+\frac{21-x}{997}+\frac{17-x}{999}+2=\frac{11-x}{334}+6\)

\(\Rightarrow\frac{25-x}{995}+\frac{1990}{995}+\frac{21-x}{997}+\frac{1994}{997}+\frac{17-x}{999}+\frac{1998}{999}=\frac{11-x}{334}+\frac{2004}{334}\)

\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}=\frac{2015-x}{334}\)

\(\Rightarrow\frac{2015-x}{995}+\frac{2015-x}{997}+\frac{2015-x}{999}-\frac{2015-x}{334}=0\)

\(\Rightarrow\left(2015-x\right)\left(\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\right)=0\)

\(\Rightarrow2015-x=0\left(\text{vì }\frac{1}{995}+\frac{1}{997}+\frac{1}{999}+\frac{1}{334}\ne0\right)\)

\(\Rightarrow x=2015\)

\(\frac{26-x}{995}\)+2+\(\frac{22-x}{997}\)+\(\frac{18-x}{999}\)+2=\(\frac{12-x}{334}\)+6

\(\frac{2016-x}{995.2}\)+\(\frac{2016-x}{997.2}\)+\(\frac{2016-x}{999.2}\)-\(\frac{2016-x}{334.6}\)=0

(2016-x)(\(\frac{1}{995.2}\)+\(\frac{1}{997.2}\)\(\frac{1}{999.2}\)-\(\frac{1}{334.6}\))=0

Dễ thấy giá trị biểu thức trong ngoặc thứ 2 khác 0

Nên 2016-x=0=>x=2016

Vậy giá trị của x là 2016

\(11999< x< 17009\)

\(\Rightarrow x=12000;13000;14000;15000;16000;17000\) (x là số tròn nghìn)

Các giá trị thỏa mãn  x :  12000 ; 13000 ; 14000 ; 15000 ; 16000 ; 17000

333333000000

a)\(x=1482-\left(175+1225\right)=1482-1400=82\)

b)\(x=\left(1000-750\right)+850=1100\)

c)\(x=999-\left(999-921\right)=999-78=921\)

a) \(\text{ x + 175 + 1225 = 1482}\)

     \(x+175=1482-1225\)

     \(x+175=257\)

     \(x=257-175\) 

     \(x=82\)

b) \(\text{ x – 850 + 750 = 1000}\)

     \(x-850=1000-750\)

     \(x-850=250\)

     \(x=1100\)

c) \(\text{ 999 – x = 999 - 921}\)

     \(999-x=78\)

               \(x=999-78\)

               \(x=921\)